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ahrayia [7]
1 year ago
11

What is the end behavior of the function f of x equals 3 times the cube root of x? as x → –[infinity], f(x) → –[infinity], and a

s x → [infinity], f(x) → [infinity]. as x → –[infinity], f(x) → [infinity], and as x → [infinity], f(x) → –[infinity]. as x → –[infinity], f(x) → 0, and as x → [infinity], f(x) → 0. as x → 0, f(x) → –[infinity], and as x → [infinity], f(x) → 0.
Mathematics
1 answer:
geniusboy [140]1 year ago
7 0

The function f(x)=4\sqrt[3]{x} is a cube root function and the function end behavior is: x → + ∞, f(x) → + ∞, and as x → - ∞, f(x) → + ∞

<h3>What is end behavior?</h3>
  • The end behavior of a function f defines the behavior of the function's graph at the "ends" of the x-axis.
  • In other words, the end behavior of a function explains the graph's trend when we look at the right end of the x-axis (as x approaches +) and the left end of the x-axis (as x approaches ).

To determine the end behavior:

  • The equation of the function is given as: f(x)=4\sqrt[3]{x}
  • To determine the end behavior, we plot the graph of the function f(x).
  • We can see from the accompanying graph of the function:
  • As x approaches infinity, so does the function f(x), and vice versa.
  • As a result, the function end behavior is:  

x → + ∞, f(x) → + ∞, and as x → - ∞, f(x) → + ∞

Therefore, the function f(x)=4\sqrt[3]{x} is a cube root function and the function end behavior is: x → + ∞, f(x) → + ∞, and as x → - ∞, f(x) → + ∞

Know more about functions' end behavior here:

brainly.com/question/1365136

#SPJ4

The complete question is given below:

What is the end behavior of the function f of x equals negative 4 times the cube root of x?

As x → –∞, f(x) → –∞, and as x → ∞, f(x) → ∞.

As x → –∞, f(x) → ∞, and as x → ∞, f(x) → –∞.

As x → –∞, f(x) → 0, and as x → ∞, f(x) → 0.

As x → 0, f(x) → –∞, and as x → ∞, f(x) → 0.

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If ST=19 and S lies at -4 , where could T be located?
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Answer:

15 or -23

Step-by-step explanation:

I think you probably already turned this in but in case you haven't:

ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?

So there's two directions we could go.

Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)

But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)

Please mark as Brainliest! :)

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kow [346]

Answer:

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Step-by-step explanation:

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