Ask question

Ask question

All categories

4 years ago

15

The function f(x)=x2. The graph ofg(x) is f(x) translated to the left 6 units and down 5 units. What is the functionrule for g(x

)?

1 answer:

Nonamiya [84]4 years ago

3 0

Add 6 to x^2 to translate function to the left (x+6)^2, then minus 5 to move down: (x-6)^2-5

You might be interested in

Twenty boys signed up for the school play. The number of girls who signed up was 195% of the number of boys. At the auditions, o

Firlakuza [10]

20 boys signed up
# of girls who signed up was 195% of the number of boys who signed up

Find 195% of 20:

1.95 * 20 = 39

So 39 girls signed up.

To find out what percent of girls who signed up for the play attended the auditions, divide 26 to the total number of girls who signed up:

26 / 39 = 0.666666667

Multiply by 100:

0.666666667 * 100 = 66.6666667%

So approximately 66.67% or 66 2/3%

7 0

3 years ago

Given: Inscribed △ABC

nexus9112 [7]

Answer:

$AB=20\sin 80^{\circ}\approx 19.7\ in\\ \\AC=20\sin 65^{\circ}\approx 18.1\ in\\ \\BC=20\sin 35^{\circ}\approx 11.5\ in$

Step-by-step explanation:

In triangle ABC, OA = OB = OC = 10 in. These segments are radii of sircumscribed circle. So, R = 10 in.

The sum of all interio angles is 180°, so

m∠C=180°-35°-65°=80°

Use the sine theorem,

$\dfrac{AB}{\sin C}=\dfrac{AC}{\sin B}=\dfrac{BC}{\sin A}=2R$

Thus,

$\dfrac{AB}{\sin 80^{\circ}}=\dfrac{AC}{\sin 65^{\circ}}=\dfrac{BC}{\sin 35^{\circ}}=20$

Therefore,

$AB=20\sin 80^{\circ}\approx 19.7\ in\\ \\AC=20\sin 65^{\circ}\approx 18.1\ in\\ \\BC=20\sin 35^{\circ}\approx 11.5\ in$

7 0

3 years ago

Write the quadratic equation whose roots are 3 and -5, and whose leading coefficient is 2.

Rainbow [258]

$\begin{cases} x=3\implies &x-3=0\\ x=-5\implies &x+5=0 \end{cases}\qquad \implies\qquad a(x-3)(x+5)=\stackrel{0}{y} \\\\\\ a(\stackrel{F~O~I~L}{x^2+2x-15})=y\implies \stackrel{\textit{leading coefficient of 2}}{2(x^2+2x-15)}=y\implies 2x^2+4x-30=y$

Check the picture below.

5 0

2 years ago

Which identify could be used to rewrite the expression x6-27

hammer [34]

The differnce of 2 perfect cubes

remember
a³-b³=(a-b)(a²+ab+b²)

so
$(x^2)^3-(3)^3=(x^2-3)(x^2+3x+9)$

3 0

3 years ago

The point (-4‚-2) lies on a circle. What is the length of the radius of this circle if the center is located at (-8‚-10)

MAVERICK [17]

Answer:

<em>4√5</em>

Step-by-step explanation:

The length of the radius of the circle will be the distance between the two coordinates. Using the formula:

D = √(x₂-x₁)²+(y₂-y₁)²

Given the coordinates (-4‚-2) and (-8‚-10)

R = √(-8-(-4))²+(-10-(-2))²

R = √(-4)²+(-8)²

R = √16+64

R = √80

R = √16*5

R = 4√5

<em>Hence the length of the radius of this circle is 4√5</em>

5 0

3 years ago