I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.
</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct
</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct
</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>
Answer:
y+2= 3(x+1)
Step-by-step explanation:
First you need to find slope by using y2-y1/x2-x1
you should get 3 for your slope(m)
Them you chose any point iḿ using (-1, -2)
The formula for point slope form is...
y-y1=m(x-x1)
plug those numbers in and you get
y + 2 = 3(x + 1)
Answer:
A. 7 1/6
Step-by-step explanation:
10 3/4 * 2/3=
43/4 * 2/3= 86/12
86/12 = 7 2/12 = 7 1/6
Answer:
<h2>2.2</h2>
Step-by-step explanation:
Use the cosine law:
![BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)](https://tex.z-dn.net/?f=BC%5E2%3DAB%5E2%2BAC%5E2-2%28AB%29%28AC%29%5Ccos%28%5Cangle%20A%29)
We have:
![BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848](https://tex.z-dn.net/?f=BC%3Da%5C%5C%5C%5CAB%3D4%5C%5C%5C%5CAC%3D3%5C%5C%5C%5Cm%5Cangle%20A%3D32%5Eo%5Cto%5Ccos32%5Eo%5Capprox0.848)
Substitute:
![a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2](https://tex.z-dn.net/?f=a%5E2%3D4%5E2%2B3%5E2-2%284%29%283%29%280.848%29%5C%5C%5C%5Ca%5E2%3D16%2B9-20.352%5C%5C%5C%5Ca%5E2%3D4.648%5Cto%20a%3D%5Csqrt%7B4.648%7D%5C%5C%5C%5Ca%5Capprox2.2)
Answer:
9m^2 - 4m - 6
Step-by-step explanation: hope this helps!