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Snezhnost [94]
1 year ago
11

In △MDK, m=16.4, d=22, and k=19. Identify m∠D rounded to the nearest degree. The figure shows triangle M D K. The length of side

M D is k units. The length of side D K is m units. The length of side K M is d units.
Answers;
a) 46°
b) 58°
c) 76°
d) 14°
Mathematics
1 answer:
Alex_Xolod [135]1 year ago
6 0

The length of the sides,MD, DK, and KM gives the measure of the angle m<D as c) 76°

<h3>Which method can be used to find the measure of angle m<D?</h3>

In triangle ∆MDK, we have;

m = 16.4

d = 22

k = 19

Using cosine rule, we get;

d² = m² + k² - 2•m•k•cos(D)

Therefore;

2•m•k•cos(D) = m² + k² - d²

D = arccos \left( \frac{ {m}^{2} +  {k}^{2}  -  {d}^{2}   }{2 \cdot m \cdot k}  \right)

Which gives;

D = arccos \left( \frac{ {16.4}^{2} +  {19}^{2}  -  {22}^{2}   }{2  \times  16.4  \times  19}  \right)  \approx  {76}^{ \circ}

  • m<D = 76°

The correct option is therefore;

  • c) 76°

Learn more about the rule of cosines here:

brainly.com/question/4316134

#SPJ1

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