Answer:
13.22
Step-by-step explanation:
were solving for t and we know:
a(t)=p(1+(r/n))^nt
5000=a-the total
2940=p-the starting amount
.041=r-the rate
1=n-compound (annual)
plug this into a graph :
5000=2940(1+(.041/1))^x
and you get : 13.22
<u>Options B and D</u>
6x² + x - 1 = 0
6x² + 3x - 2x - 1 = 0
3x(2x + 1) - 1(2x + 1) = 0
(3x - 1)(2x + 1)
x = 1/3 and -1/2
4 months
False
NO