A person invest $2,940 in an account tgat earns 4.1% annual intrest. Find when the value of the investment reaches 5,000. If nec
essary round to the nearest tenth
1 answer:
Answer:
13.22
Step-by-step explanation:
were solving for t and we know:
a(t)=p(1+(r/n))^nt
5000=a-the total
2940=p-the starting amount
.041=r-the rate
1=n-compound (annual)
plug this into a graph :
5000=2940(1+(.041/1))^x
and you get : 13.22
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The answer is
The expression is
Since
, then:
Answer:
$2,142 decrease
$39,858 next model price
Step-by-step explanation:
$42,000 x .051 = $2,142
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(-6)-(+2)= -8
(-9)-(-8)= -17
(-6)-(+6)= -12
(-8)-(-8)= -16
(+5)-(+1)= 4
(+6)-(-2)= 8
(-3)-(+5)= -8
(-8)-(+5)= -13
(-9)-(-4)= -13
(+1)-(+3)= -2
(-3)-(+8)= -11
(+9)-(-4)= 13
(+8)-(-7)= 15
(-6)-(+3)= -9
(-3)-(+4)= -7
(-4)-(+3)= -7
(-6)-(+1)= -7
(+8)-(-8)= 16
(+1)-(+4)= -3
(+7)-(+9)= -2
(+5)-(-5)= 10
(+6)-(-9)= 15
(+7)-(-5)= 12
(+2)-(+1)= 1
(-6)-(+3)= -9
(+2)-(+9)= -7
(+1)-(+1)= 0
(-2)-(+3)= -5
(+3)-(+4)= -1
(+8)-(-9)= 17
