A. f(1)=5 (as defined on the second line, x=1) TRUE because f(1)=5
B. f(5)=5^2=25 (as defined on third line, x>1) FALSE because f(5) ≠ 1
C. f(-2)=2(-2)=-4 (as defined on first line, x<1) FALSE because f(-2) ≠ 4
D. f(2)=2^2=4 (as defined on third line, x>1) TRUE because f(2)=4
The equation of the volume of a cone is,
V = (1/3)Bh
where B is the area of the base and h is the height. The solid that we are looking for is that which has an equation of
V = Bh
for the volume. The answer is <em>CYLINDER. </em>
The x-value at the y-intercept is 0. The y-value there is 2. As the x-value increases by 1 unit to x=1, the y-value decreases by 1 unit to y=1. Thus, the slope is -1, and the slope-intercept form of the equation can be written as
... y = -x + 2
Subtracting the right side puts the equation into general form.
... x + y - 2 = 0
I got F^-1(x) = x/4 + 4/9.
I believe the answer is B.
Answer:
A= 695.3cm²
Step-by-step explanation:
- We khow that the area of anctagon is : A= 2(1+)*a² with a the side
- so A= 2(1+√2)*a² = 695.29= 695.3 cm²