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S_A_V [24]
1 year ago
15

How many lbs of peanuts must mike add to 9 lbs of mixed nuts containing 40% peanuts to make a mixture with 73% peanuts

Mathematics
1 answer:
andreev551 [17]1 year ago
3 0

The new mixture exists 56.5% peanuts.

<h3>How to estimate the total number of peanuts required for the mixture?</h3>

The first batch of 9 lb of mixed nuts possesses 40% peanuts.

This means the quantity of peanuts exists:

9 * 40/100 = 3.6 lb

The second batch of 9 lb of mixed nuts possesses 73% peanuts.

This means the quantity of peanuts exists:

9 * 73/100 = 6.57 lb

The total quantity of peanuts in the mix exists

3.6 lb + 6.57 lb = 10.17 lb

There exist 9 lb + 9 lb = 18 lb of mix.

Therefore, the percent of peanuts in the mix exists:

10.17 / 18 * 100 = 56.5%

The new mixture exists 56.5% peanuts.

To learn more about the total quantity refer to:

brainly.com/question/18919760

#SPJ4

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