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2 years ago

5

Fill in each box with the correct number or variable 5(x+9)=5 • + 5 •

1 answer:

photoshop1234 [79]2 years ago

4 0

Step-by-step explanation:

5(x + 9) = 5*x + 5*9

which is

5x + 45

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Explain how to solve the equation and then check the solution.<br><br> 9 = q – 4

Vika [28.1K]

Assignment: $\bold{Solve \ And \ Check \ Equation: \ 9=q-4}$

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Answer: $\boxed{\bold{q=13}}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Switch Sides

$\bold{q-4=9}$

[ Step Two ] Add 4 To Both Sides

$\bold{q-4+4=9+4}$

[ Step Three ] Simplify

$\bold{q=13}$

[ Step Four ] Check Your Work

$\bold{13 \ - \ 4 \ = \ 9}$

[ Step Five ] Question: Is Equation Correct

$\bold{Equation \ Is \ Correct, \ Therefore \ q=13}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

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3 years ago

Read 2 more answers

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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Answer:

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3 years ago

[A] is making 25 sundaes with mint, chocolate, and vanilla ice cream.

qwelly [4]

Answer:

-2.5

Step-by-step explanation:

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3 years ago

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4 years ago