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Paul [167]
3 years ago
10

9 markers cost $11.50. How much would 7 markers cost?

Mathematics
2 answers:
Anna007 [38]3 years ago
8 0

Answer:

7 markers cost $8.95

Step-by-step explanation:

9x = 11.50

x = 11.5/9 = 1.278

Therefore, 7 markers, or 7x = 7(1.278) = 8.946

kicyunya [14]3 years ago
7 0

Answer:

5.48

Step-by-step explanation:

​11.50

​

0.782609=\frac{x}{7}0.782609=

5.478261=x5.478261=x

4 Switch sides.

x=5.478261x=5.478261

the answer is 5.48

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Over 5 days, Skylar sheared 300 sheep. How many would she be able to shear in 26 days?
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At a department store, Kendra has a debt greater than $25.00. Which could be Kendra’s balance?
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The second choice is the correct one

Explanation:
(2x+3)^2 + 8(2x+3) + 11 = 0
To use the u substitution, we will assume that:
2x + 3 = u

Substitute with this in the given expression, we will get:
u^2 + 8u + 11 = 0 

The general form of the second degree equation is:
ax^2 + bx + c = 0

Comparing the expression we reached with the general one, we will find that:
a = 1
b = 8
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The roots can be found using the rule found in the attached picture.
This means that, for the given expression:
u = -4 ± √5 

Now, we have:
u = 2x+3
This means that:
at u = -4 + √5 
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x = (-7 + √5) / 2

at u = -4 - √5 
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This means that, for the given expression:
x = (-7 ± √5 ) / 2

Hope this helps :)

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