Pregnancy. the body needs to gather nd make a new set of cells to build the baby
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
Answer:
Is released into the air through stomata
Explanation:
Oxygen and hydrogen both exists as gaseous molecules in the atmosphere. However, one of them (oxygen) is a product of photosynthesis while the other (hydrogen) is one of the constituents of the molecule that starts the process of photosynthesis.
According to this question, the X used in the attached diagram is the role of oxygen in photosynthesis. Oxygen is released as a product of photosynthesis and goes out of the plant into the air via the STOMATA. Hence, the gas released into the air via stomata is OXYGEN.
Platinum: Mostly mined around that area.
Recessive genetic disorders result from inheriting 2 defective recessive alleles of gene ( one from each parent ). The x - chromosome holds about 10% of all human genes. Sex chromosomes are: males XY, females XX. Y-traits occure in males only. Y-disorders are rare.
Answer: Most recessive disorders are on the Autosomal recessive gene, and thus not x-linked.
