The voltage of the given concentration cell ,made up off copper electrodes is 0.0047 V.
Calculation:
The concentration of the two cells are =0.45 m and 0.65 m
In general, the reaction at the cathode is-
+ 2e⁻ →
And the reaction at the anode is-
→ + 2e⁻
In general, the reaction of the cell is -
→
At the initial stage, the voltage V= 0 v
Normally the voltage of the cell at 25° is -
E = V - log
where n= the number of electrons. here n= 2.
Hence, from the equation, we have to find out the voltage of the concentration cell.
E = 0 - (0.0591/ 2) log (0.45/0.65)
E= 0 - (-0.00471)
E= 0.00471 V
Therefore, from the above calculation, it is concluded that the voltage of the concentration cell is 0.0047V.
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