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1 year ago

13

Many modern can designs include a ring pull that allows the

1 answer:

Arada [10]1 year ago

3 0

Answer:

Consumers not having a can opener readily available

Explanation:

More people will be likely to buy a product that is easy to use. For example, yogurt cups have pull tabs in order to open the yogurt without leaving any cover attached. Ease of use is one of the key main design constraints when designing consumer goods.

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Wastewater flows into a _________ once it is released into a floor drain.

vodomira [7]

Answer:

a

Explanation:

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3 years ago

A vacuum gage connected to a tank reads 30 kPa at a location where the barometric reading is 755 mmHg. Determine the absolute pr

navik [9.2K]

Answer:

Absolute pressure=70.72 KPa

Explanation:

Given that Vacuum gauge pressure= 30 KPa

Barometer reading =755 mm Hg

We know that barometer always reads atmospheric pressure at given situation.So atmospheric pressure is equal to 755 mm Hg.

We know that P= ρ g h

Density of $Hg=13600 \frac{kg}{m^3}$

So P=13600 x 9.81 x 0.755

P=100.72 KPa

We know that

Absolute pressure=atmospheric pressure + gauge pressure

But here given that 30 KPa is a Vacuum pressure ,so we will take it as negative.

Absolute pressure=atmospheric pressure + gauge pressure

Absolute pressure=100.72 - 30 KPa

So

Absolute pressure=70.72 KPa

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2 years ago

What does an engineer do? List as many types of engineers as you can.

BARSIC [14]

Answer:

Mechanical Engineering

Chemical Engineering

Civil Engineering

Explanation:

I got it from my old homework And I learn those at school ( Thank You For The Points)

7 0

2 years ago

An inductor has a 50.0-Ω reactance when connected to a 60.0-Hz source. The inductor is removed and then connected to a 45.0-Hz s

nignag [31]

Given:

$X_{L} = 50.0 \ohm$

frequency, f = 60.0 Hz

frequency, f' = 45.0 Hz

$V_rms} = 85.0 V$

Solution:

To calculate max current in inductor, $I_{L(max)$ :

At f = 60.0 Hz

$X_{L} = 2\pi fL$

$50.0 = 2\pi\times 60.0\times L$

L = 0.1326 H

Now, reactance $X_{L}$ at f' = 45.0 Hz:

$X'_{L} = 2\pi f'L$

$X'_{L} = 2\pi\times 45.0\times 0.13263 = 37.5\ohm$

Now, $I_{L(max)$ is given by:

$I_{L(max) = \sqrt {\frac{2V_{rms}}{X'_{L}}}$

$I_{L(max) = \sqrt {\frac{2\times 85.0}{37.5}} = 2.13 A$

Therefore, max current in the inductor, $I_{L(max)$ = 2.13 A

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3 years ago

How do you make a robotic dog

fredd [130]

In order to create a robotic dog, you are needing the necessary parts to create Goddard from Jimmy nutreon boy genius

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3 years ago

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