Answer: The uncertainty in the measurements is 4%
Explanation: uncertainty is the doubt or level of not being sure about an outcome or a result.
Because the volume of the cylinder is gotten by measuring length and diameter of the cylinder, using a micrometer that has a 0.5% uncertainty, this will cause the measurements of each value to have a 0.5% uncertainty.
Therefore, since the length has 0.5% uncertainty and the diameter has 0.5% uncertainty too.
The uncertainty in the measurement will be.
0.5% + 0.5% = 1%
Since we are told that this measurement was carried out in four different locations, that means the uncertainty will become;
1% × 4 = 4%
As the number of locations increases, the uncertainty in the measurement will increase as well.
Answer:
You should follow the officer's instruction and proceed with caution
Explanation:
You should always follow the lawful orders of an officer regardless of standard traffic procedures. This is typical because the officer needed to take control of a particular situation due to a crash or other potential hazard, making manual commands safer than standard road rules.
Answer:
specific volume = 1.025 m³/kg
Explanation:
given data
total mass m1 +m2 = 80 kg
specific volume = 0.8 m³/kg
occupies volume v1 = 40 m³
other gas specific volume = 1.4 m³
to find out
How much volume is occupied by the second gas and what is the specific volume of the mixture
solution
we know that density is reciprocal of specific volume and here gas is not interacting
so total specific volume is assume so ratio is total volume to total mass
and
specific volume = 
here ρ is density
so ρ1 = 
= 1.25 kg/m³
and ρ2 = 
= 0.714 kg/m³
and
so m1 = ρ1v1 = 1.25 × 40 = 50 kg
and m2 = 80 - 50 = 30 kg
so
v2 = 
v2 = 
= 42 m³
so volume occupied by second das = 42 m³
and
specific volume of mixture will be
specific volume of mixture = 
specific volume = 
specific volume = 1.025 m³/kg
Answer:
23 W/K
Explanation:
Entropy of water at 15°C is 224.5 J/kg/K.
Entropy of water at 15.2°C is approximately 227.4 J/kg/K (interpolated).
The increase in entropy is therefore:
227.4 J/kg/K − 224.5 J/kg/K = 2.9 J/kg/K.
So the rate of entropy generation is:
2.9 J/kg/K × 8 kg/s = 23.2 W/K
Rounded to two significant figures, the rate is 23 W/K.
Answer:
a) 254.6 GPa
b) 140.86 GPa
Explanation:
a) Considering the expression of rule of mixtures for upper-bound and calculating the modulus of elasticity for upper bound;
Ec(u) = EmVm + EpVp
To calculate the volume fraction of matrix, 0.63 is substituted for Vp in the equation below,
Vm + Vp = 1
Vm = 1 - 0.63
Vm = 0.37
In the first equation,
Where
Em = 68 GPa, Ep = 380 GPa, Vm = 0.37 and Vp = 0.63,
The modulus of elasticity upper-bound is,
Ec(u) = EmVm + EpVp
Ec(u) = (68 x 0.37) + (380 x 0.63)
Ec(u) = 254.6 GPa.
b) Considering the express of rule of mixtures for lower bound;
Ec(l) = (EmEp)/(VmEp + VpEm)
Substituting values into the equation,
Ec(l) = (68 x 380)/(0.37 x 380) + (0.63 x 68)
Ec(l) = 25840/183.44
Ec(l) = 140.86 GPa
