Ik rp because the i forgot the sc
2 answers:
Answer:
Step-by-step explanation:
This is a geometric mean problem...a ratio. The geometric mean is the height of the triangle, 6. To solve:
and cross multiply to solve for x:
3x = 36 so
x = 12
Answer: x=12
Step-by-step explanation:
We know that there are 2 right angles. This means that there must be a ratio involved. a/b=a/b.
In the smaller triangle, a=3, b=6, so the ratio is 3/6.
In the larger triangle, a=6, b=x, so the ratio is 6/x.
Place them equal to each other to solve.
Use the butterfly method to solve (cross-multiply).
Divide both sides by 3 to isolate the variable
There's your answer! Hope this helps :))
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step 1
multiply by
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step 2
Divide numerator and denominator by
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the answer is
First, let's use the given information to determine the function's amplitude, midline, and period.
Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.
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Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.