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GenaCL600 [577]
2 years ago
7

Find a power series representation for the function. (give your power series representation centered at x = 0. ) f(x) = ln(5 − x

)
Mathematics
1 answer:
klio [65]2 years ago
3 0

Recall that for |x|, we have the convergent geometric series

\displaystyle \sum_{n=0}^\infty x^n = \frac1{1-x}

Now, for \left|\frac x5\right| < 1, we have

\dfrac1{5 - x} = \dfrac15 \cdot \dfrac1{1 - \frac x5} = \dfrac15 \displaystyle \sum_{n=0}^\infty \left(\frac x5\right)^n = \sum_{n=0}^\infty \frac{x^n}{5^{n+1}}

Integrating both sides gives

\displaystyle \int \frac{dx}{5-x} = C + \int \sum_{n=0}^\infty \frac{x^n}{5^{n+1}} \, dx

\displaystyle -\ln(5-x) = C + \sum_{n=0}^\infty \frac{x^{n+1}}{5^{n+1}(n+1)}

If we let x=0, the sum on the right side drops out and we're left with C=-\ln(5).

It follows that

\displaystyle \ln(5-x) = \ln(5) - \sum_{n=0}^\infty \frac{x^{n+1}}{5^{n+1}(n+1)}

or

\displaystyle \ln(5-x) = \boxed{\ln(5) - \sum_{n=1}^\infty \frac{x^n}{5^n n}}

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