Mathematically speaking, the Riemann sum of the <em>linear</em> function is represented by A ≈ [[4 - (- 6)] / 5] · ∑ 2 [- 6 + i · [[4 - (- 6)] / 2]] - [[4 - (- 6)] / 5] · ∑ 1, for i ∈ {1, 2, 3, 4, 5}, whose representation is represent by the graph in the lower left corner of the picture.
<h3>What figure represents a Riemann sum with right endpoints?</h3>
Graphically speaking, Riemann sums with <em>right</em> endpoints represent a sum of <em>rectangular</em> areas with equal width with <em>excess</em> area for <em>positive</em> y-values and <em>truncated</em> area for <em>negative</em> y-values generated with respect to the x-axis. Mathematically speaking, this case of Riemann sums is described by the following expression:
A ≈ [(b - a) / n] · ∑ f[a + i · [(b - a) / n]], for i ∈ {1, 2, ..., n}
Where:
a - Lower limit
b - Upper limit
n - Number of rectangles
i - Index of a rectangle
If we know that f(x) = 2 · x - 1, a = - 6, b = 4 and n = 5, then the Riemann sum with right endpoints of the area below the curve is:
A ≈ [[4 - (- 6)] / 5] · ∑ 2 [- 6 + i · [[4 - (- 6)] / 2]] - [[4 - (- 6)] / 5] · ∑ 1, for i ∈ {1, 2, 3, 4, 5}
To learn more on Riemann sums: brainly.com/question/21847158
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