The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
oh well thanks
Step-by-step explanation:
Answer:

Step-by-step explanation:
Please refer to the image attached with this answer. Assuming our triangle to be ΔABC and Line AD meeting BC at D.
As we are given that side b = side c
The angle subtended by them ∠B and ∠C must be equal . Let us assume them to be x each . hence
x + x + 52° +31° = 180°
2x + 73° = 180°
2x = 180°- 73°
2x = 107 °
x = 53.5°
Hence in ΔACD
x+ 31°+∠2= 180°
53.5°+31°+ ∠2 = 180°
∠2=180°-84.5°
∠2=95.5°
Also
∠1 + ∠2 = 180°
∠1 + 95.5° = 180°
∠1 = 180°-95.5°
∠1 =84.5°
Now applying Sine rule in ΔABD




Hence we have c as 15.14
as we are given that side c = side b , b=15.14
The properties of any triangle says that the sum of two sides of any triangle is always greater than the third side. Hence
a<b+c
12+2x-6<15.14+15.14
6+2x<30.28
2x<30.28-6
2x<24.28
x<12.14
also side a must be greater than 0
12+2x-6>0
6+2x>0
2x>-6
x>-3
Hence the range of x will be
-3 <x < 12.14
Answer:
x = 38
Step-by-step explanation:
x-13 = 25
Add 13 to each side
x-13+13 = 25+13
x = 38
Check
38-13 = 25
25=25
1. Distributive Property.
2.Congruence Property.
3.Subtraction Property.
4.Division Property.