Using the relation between velocity, distance and time, it is found that:
- The rate of the plane in still air is of 140 mph.
- The rate of the wind is of 40 mph.
<h3>What is the
relation between velocity, distance and time?</h3>
Velocity is <u>distance divided by time</u>, that is:

A plane traveling with the wind travels 900 miles in 5 hours, hence:


The return trip is against the wind and takes 9 hours, hence:


From the first equation, we have that:
![v_w = 180 - v_a{/tex]Replacing on the second:[tex]v_a - v_w = 100](https://tex.z-dn.net/?f=v_w%20%3D%20180%20-%20v_a%7B%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EReplacing%20%3C%2Fstrong%3Eon%20the%20second%3A%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_a%20-%20v_w%20%3D%20100)



[tex]v_w = 180 - 140 = 40{/tex]
Hence:
- The rate of the plane in still air is of 140 mph.
- The rate of the wind is of 40 mph.
More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569
We are given here the individual costs of DVD and CD as well as the total sales and the number of items sold on one day. To solve the number of DVDs and CDs sold each, we devise two independent linear equations:
(1) x + y = 39
(2) 4x + 7y = 204
x- number of DVDs; y - number of CDs
solving, x= 23 DVDs
Answer:
D
Step-by-step explanation: