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andreyandreev [35.5K]
3 years ago
10

Help me please m, it due soon

Mathematics
1 answer:
allsm [11]3 years ago
5 0
Surface area= 2(6x15)+2(7x15)+2(6x7)
=180+210+84
=474m

Volume=15x6x7
=630m^2
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What is the slope of the line shown in the graph?
stira [4]
Y= f(x)= ax+b
when x= -1, y= -1
-1= -a+b   | * ( -1)

when x= -3, y=2
2= -3a+b

-3a+b= 2
a -  b=  1
--------------
2a=3
a=3/2   is the slope


7 0
3 years ago
The length of XY the minor arc is 48 cm what is the circumference of Z
Amanda [17]
If found the image that accompanies this problem, the central angle was 60°. Since the circumference of a circle is always 360°, the minor arc represents 60°/360° of the circle.

48 cm / (60°/360°) = 48 cm / (1/6) = 48 cm * 6/1 = 48 cm * 6 =  288 cm

The circumference of circle Z is 288 cm.

4 0
3 years ago
Read 2 more answers
Morgan works at a store that sells clothing accessories. The supply function
jarptica [38.1K]

Answer:

The number of supply of base balls is 22

Step-by-step explanation:

Given

P = Q - 4

Price = $18

Required

Number of supply

The relationship between price and quantity is given to be P = Q - 4 where price is represented by P and Q represents the quantity.

To get the quantity supply when price is $18, all you need to do is to substitute 18 for P in the above equation;

Thus, giving:

18 = Q - 4

Make Q the subject of formula

Q = 18 + 4

Q = 22 quantities

Hence,  the number of supply of base balls is 22

6 0
3 years ago
Read 2 more answers
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
The prism shown has a volume of 798 cm3.
a_sh-v [17]

Answer:

10.5 cm

Step-by-step explanation:

Volume = base area × height

798 = (9.5 × 8) × height

height = 798/76

height = 10.5

4 0
3 years ago
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