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3 years ago

Plz help for financial algebra

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

Answer: $277.91

<u>Step-by-step explanation:</u>

The average of the 2 highest salaried quarters is:

$\dfrac{\$13,500+\$12,775}{2}=\dfrac{\$26,275}{2}=\$3,137.50$

Divide that by 26 (weeks) to find out her average weekly salary:

$\dfrac{\$3,137.50}{26}=\$505.29$

Multiply that by 55% (0.55) to calculate her weekly unemployment benefit:

$\$505.29(0.55)=\$277.908$

Round to the nearest penny --> $277.91

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just olya [345]

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7 0

3 years ago

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A baby elephant weighs 200 pounds at birth. Seven years later, the elephant's weight is 3,000 pounds.

lawyer [7]

Answer:

A - 7*400 = 2800 + 200 = 3000

8 0

3 years ago

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What is 3 2/3 divided by 2 1/6

julsineya [31]

Answer:

Exact form:

22/13

Decimal form:

1.692307

4 0

3 years ago

I need help on these questions can u make sure u do all of them cuz some people just only do one problem.

charle [14.2K]

Answer:

Ans. = 18

Step-by-step explanation:

= -1 (-1)(-3)(-6)

= 1×18

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3 years ago

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Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

3 years ago