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Andreyy89
2 years ago
7

3(h + 1) + 2 = 20 how do I find h?

Mathematics
2 answers:
romanna [79]2 years ago
8 0
H will be 5 because 3h+3+2=20 3h+5=20 20-5 3h=15
Evgesh-ka [11]2 years ago
7 0

Answer:

h = 5

Step-by-step explanation:

3(h + 1) + 2 = 20 ( subtract 2 from both sides )

3(h + 1) = 18 ( divide both sides by 3 )

h + 1 = 6 ( subtract 1 from both sides )

h = 5

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A^10x^7xc^12 divided by 7^6xb^4xc^12
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Step-by-step explanation:

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2 years ago
What is 2x-3=15 i need help
Bingel [31]

Answer:

x = 9

Step-by-step explanation:

2x - 3 = 15

2x = 15 + 3

2x = 18 (divide both sides by 2 to get x)

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x = 9

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3 years ago
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1 year ago
Judys brother sam has a collection of 96 comic book. What are the ten way sam could divide his comic books into equal groups?
Georgia [21]
We have been given that Judy’s brother Sam has a collection of 96 comic books.
We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as .
Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
4 0
2 years ago
Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.
NemiM [27]

Complete question is;

Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.

1) 2x + y = 10

x - 3y = -2

2) x + 2y = 5

2x + y = 4

3) x + 3y = 5

6x - y = 11

4) 2x + y = 10

-6x - 3y = -2

Answer:

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Step-by-step explanation:

1) 2x + y = 10 - - - (eq 1)

x - 3y = -2 - - - (eq 2)

Multiply eq 1 by 3 to get;

6x + 3y = 30

Add it to eq 2 to get;

7x = 28

x = 28/7

x = 4

2) x + 2y = 5 - - - (eq 1)

2x + y = 4 - - - (eq 2)

Multiply eq 2 by 2 to get;

4x + 2y = 8

Subtract eq 1 from it to get;

3x = 3

x = 3/3

x = 1

3) x + 3y = 5 - - - (eq 1)

6x - y = 11 - - - (eq 2)

Multiply eq 2 by 3 to get;

18x - 3y = 33

Add to eq(1) to get;

19x = 38

x = 38/19

x = 2

4) 2x + y = 10 - - - (eq 1)

-6x - 3y = -2 - - - (eq 2)

Make y the subject in eq 1 to get;

y = 10 - 2x

Put in eq (2);

-6x - 3(10 - 2x) = -2

-6x - 30 + 6x = -2

0 = 0

Thus,no solution exists.

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

3 0
3 years ago
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