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Licemer1 [7]
3 years ago
8

Mario invested $5100 $ ⁢ 5100 at 13% 13 % to be compounded daily. What will be the value of Mario's investment in 2 2 years? Rou

nd your answer to the nearest cent, if necessary. Note: 365 365 days in a year and 30 30 days in a month.
Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

lets see

Step-by-step explanation:

You might be interested in
Kendra swims 126 miles in 3 days, what is the constant rate that Kendra swims per day? a. 40 miles per day c. 42 miles per day b
Leni [432]

Answer:

c. 42 miles per day

Step-by-step explanation:

From the information given, you can use a rule of three to calculate the constant rate that Kendra swims per day given that she swims 126 miles in 3 days:

3 days → 126 miles

1 day   →        x

x=(1*126)/3=42 miles

According to this, the answer is that Kendra swims 42 miles per day.

5 0
2 years ago
Consider the continuous random variable x, which has a uniform distribution over the interval from 20 to 28. refer to exhibit 6-
tatyana61 [14]
(25 -21)/(28 -20) = 4/8 = 1/2

Your probability is 1/2.
7 0
3 years ago
Sabra joins a cooking club for $8.50 and pays $6.25 each month. She also joins a movie club for $12 and pays $3.75 each month. W
podryga [215]

Simplified expression for total amount spent is 10(2.05 + m)

Step-by-step explanation:

  • Step 1: Write expression for expense on joining cooking club for m months.

Expense = 8.50 + 6.25 × m

  • Step 2: Write expression for expense on joining movie club for m months.

Expense = 12 + 3.75 × m

  • Step 3: Calculate the total amount spent on both clubs

Total Amount = 8.50 + 6.25m + 12 + 3.75m = 20.5 + 10m = 10(2.05 + m)

6 0
2 years ago
What is the approximate value of k?
lesya692 [45]

Hello from MrBillDoesMath!

Answer:

5.06

Discussion:

Angle J = 180 - (120 + 40) = 180 - 160 = 20 degrees,

From the law of sines

sin(120)/k = sin(20)/2  =>

sin(120) =  k *  (  sin(20)/2) )                (multiply both sides by "k")

k = sin(120)/  (   sin(20)/2)                    (divide both sides by sin(20)/2)

k =  (0.866) /  ( 0.171) =  5.06


Regards,  

MrB

 P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


6 0
2 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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