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2 years ago

What is the optimum ph of a sodium formate/formic acid buffer? (for formic acid, ka = 1. 7 × 10–4. )

Chemistry

1 answer:

hoa [83]2 years ago

6 0

The optimum pH of formic acid - formate buffer is 3.75

pH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base.
pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.

What is Buffer ?

A substance or a solution which resists any changes in pH, when acid or alkali is added to it.

pH = pKa + log[base] / [acid]

Considering equimolar concentration of acid and base

pH = 3.75 + log(x)/(x)

pH = 3.75 + log (1)

pH = 3.75 + 0

pH = 3.75

Hence,

The optimum pH of formic acid - formate buffer is 3.75

Learn more about pH here:brainly.com/question/16036689

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Vaselesa [24]

Answer:

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3 years ago

500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.

jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated HCl solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted HCl solution

We are given:

$M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL$

Putting values in above equation, we get:

$0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M$

Hence, the concentration of diluted solution is 0.16 M

5 0

4 years ago

A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL

ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

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3 years ago

Calculate the percent ionization of ha in a 0.10 m solution. express your answer as a percent using two significant figures.

postnew [5]

The percent would be 0.31% hope that helps

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4 years ago

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3 years ago