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Lunna [17]
3 years ago
12

Translate the words into formulas, predict the product, & balance the equations. Include states of matter.

Chemistry
1 answer:
Andreyy893 years ago
8 0
Hihihihihihihihihihihihihi
Hibiscus I
Hi yes



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Which of the following techniques is used to separate proteins by function?
Anon25 [30]

Ammonium sulfate precipitation is used to separate proteins by function

However, it is one of the most commonly used methods for laboratory scale protein purification and fractionation. This method is also used to separate proteins by altering their solubility.

<h3>What is separation techniques?</h3>

Separation technique is a process or method used to the components of mixtures.

There are different types of separation technique which includes sublimation, precipitation, sieving, evaporation and many more.

Learn more about separation techniques:

brainly.com/question/13052303

8 0
2 years ago
What is the number of orbit for calcium
CaHeK987 [17]
It has 20 electrons
7 0
3 years ago
Earth is approximately 1.5 x 10^8 km from the sun the. How far is earth from the sun meters
Zielflug [23.3K]

Answer:

{ \tt{1 \: km = 1000m}} \\ { \tt{1.5  \times {10}^{8} km =  (\frac{1.5 \times  {10}^{8} \times 1000 }{1} )m}} \\  = 1.5 \times  {10}^{11}  \: metres

4 0
3 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
If 0.25 liters of solution contains 0.030 moles of KOH what is the molarity of the solution?
sdas [7]

Answer:

The molarity of the solution is 0,12 M.

Explanation:

We calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case KOH) in 1000ml of solution (1 liter):

0,25 L solution----- 0,030 moles of KOH

1 L solution----x= (1 L solution x 0,030 moles of KOH)/0,25 L solution

x= 0,12 moles of KOH ---> <em>The solution is 0,12 M</em>

7 0
3 years ago
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