Which states of matter change shape when moved? Which states of matter change shape when moved?

Show whether the following solutes are soluble in each solvent, and the process of dissolution of each, and their weak bonds. (N

Alexeev081 [22]

Answer:

I don't really understand this...

5 0

3 years ago

Please help with this , it’s very important

timurjin [86]

Explanation:

a) Cr is acid K is base

b) Ca is base and the other left part is acid

c)Ca is base and F2 is acid

d) NH4 is acid and SO4 is base

5 0

3 years ago

What are the variables that don't change

Blababa [14]

Constant variable/control variable

7 0

3 years ago

In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant

BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

In another experiment, if 80 $XO_3$ molecules react with 104 $BrZ_3$ molecules. How many $Br_2$ molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of $BrZ_3$ react with 6 molecule of $XO_3$

So, 104 molecules of $BrZ_3$ react with $\frac{104}{8}\times 6=78$ molecule of $XO_3$

From this we conclude that, $XO_3$ is an excess reagent because the given moles are greater than the required moles and $BrZ_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of $Br_2$

From the reaction, we conclude that

As, 8 molecules of $BrZ_3$ react to give 4 molecules of $Br_2$

So, 104 molecules of $BrZ_3$ react to give $\frac{104}{8}\times 4=52$ molecules of $Br_2$

Hence, the number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

4 0

3 years ago

A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s

Alla [95]

Answer: The percent yield of the 1-bromobutane is 48.65 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)