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goldenfox [79]
2 years ago
11

Light of frequency 1.40*10^15 Hz strikes a surface, causing photoelectrons to leave with a KE of 1.05 eV. What is the work funct

ion in eV?

Chemistry
1 answer:
katrin [286]2 years ago
3 0

Work function gives the work required for an electron to be emitted from a surface. The work function emitted with photoelectrons of kinetic energy 1.05 eV is 4.74eV.

<h3>What is the photoelectric effect?</h3>

The photoelectric effect is the emission of an electron by the projected beam of light with energy greater than the work function.

The photoelectric effect is given as,

E = φ + KE

Given,

Kinetic energy of photoelectrons = 1.682 10⁻¹⁹ J (as, 1eV = 1.602 x 10⁻¹⁹ J)

Frequency = 1.40x10¹⁵ s⁻¹

Work function (φ) =?

The work function with respect to frequency is given as,

(6.623 x 10⁻³⁴Js)(1.40x10¹⁵ s⁻¹) = φ + 1.682 x 10⁻¹⁹ J

φ = (9.272 x 10⁻¹⁹) - (1.682 x 10⁻¹⁹)

φ = 7.590 x 10⁻¹⁹ J

Work function in eV is converted as, 1eV = 1.602 x 10⁻¹⁹ J

= 4.74 eV

Therefore, the work function is 4.74eV.

Learn more about work function here:

brainly.com/question/3734730

#SPJ1

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696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

P_1 = 720 mmHg              

P_2 = ?

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Formula

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