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2 years ago

2t - 9 - 6t + 2 i really need help

Mathematics

1 answer:

MakcuM [25]2 years ago

3 0

Answer:

-4t-11

Step-by-step explanation:

rearrange the numbers

2t-6t-9+2

Add negative 2

2t-6t-11

2-6

-4t-11

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What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3, 2), (8,2), and (5,-2)?

Llana [10]

Answer:

The area of the parallelogram is 20 units²

Step-by-step explanation:

* Lets explain how to solve the problem

- The vertices of the parallelogram are (0 , -2) , (3 , 2) , (8 , 2) , (5 , -2)

- The side joining the points (0 , -2) and (5 , -2) is a horizontal side

because the points have same y-coordinates

- The side joining the points (3 , 2) and (8 , 2) is a horizontal side

because the points have same y-coordinates

∴ These two sides are parallel bases of the parallelogram

∵ The length of any horizontal side = x2 - x1

∴ The length of the side = 5 - 0 = 5 <em>or</em> 8 - 3 = 5

∴ The length of one base of the parallelogram is 5 units

- The height of this base is the vertical distance between these two

parallel bases

∵ The length of any vertical distance = y2 - y1

∵ y2 = 2 and y1 = -2 ⇒ the y-coordinates of the parallel bases

∴ The length of the vertical distance = 2 - (-2) = 2 + 2 = 4 units

∵ This vertical distance between the two parallel bases is the height

of these bases

∴ The height of the parallelogram is 4 units

- The area of the parallelogram = base × height

∵ The base = 5 units and the height = 4 units

∴ The area = 5 × 4 = 20 units²

* The area of the parallelogram is 20 units²

7 0

4 years ago

I’m not sure how to do this

Cerrena [4.2K]

It's b because you have to round up

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C

MariettaO [177]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find out the gradient (Slope " m ") of line q ;

$\qquad \sf \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\qquad \sf \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}$

$\qquad \sf \dashrightarrow \:m = - 4$

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

$\qquad \sf \dashrightarrow \:y - 4 = m(x - 0)$

$\qquad \sf \dashrightarrow \:y = mx + 4$

Now, plug in the value of gradient ~

$\qquad \sf \dashrightarrow \:y = - 4x + 4$

here we can clearly observe that, the Area under the curve can easily be represented as :

$\qquad \sf \dashrightarrow \:y < - 4x + 4$

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0

2 years ago

Plllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz 100 points

tamaranim1 [39]

Answer:

z = 10

Step-by-step explanation:

the steps have been attached above

7 0

3 years ago

Read 2 more answers

Student Produced Response - Calculator

faltersainse [42]

Answer:

$\dfrac{a}{b}=0.75$ .

Step-by-step explanation:

If two equations $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$ has infinitely many solutions, then

$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$

The given equations are

$ax+by=10$

$3x+4y=20$

It is given that the above system of equations has infinitely many solutions. So,

$\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{10}{20}$

$\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{1}{2}$

Now,

$\dfrac{a}{3}=\dfrac{1}{2}$ and $\dfrac{b}{4}=\dfrac{1}{2}$

$a=\dfrac{3}{2}$ and $b=\dfrac{4}{2}$

$a=1.5$ and $b=2$

So, a=1.5 and b=2.

Now,

$\dfrac{a}{b}=\dfrac{1.5}{2}=0.75$

Therefore, $\dfrac{a}{b}=0.75$ .

5 0

4 years ago