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VLD [36.1K]
2 years ago
14

What is the fiftieth term in the sequence 5, 7, 9, 11, 13 …?

Mathematics
1 answer:
Komok [63]2 years ago
5 0

The 15th term in the given A.P. sequence is a₁₅ = 33.

According to the statement

we have given that the A.P. Series with the a = 5 and the d is 2.

And we have to find the 15th term of the sequence.

So, for this purpose we know that the

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

And the formula is a

an = a + (n-1)d

After substitute the values in it the equation become

an = 5 + (15-1)2

a₁₅ = 5 + 28

Now the 15th term is a₁₅ = 33.

So, The 15th term in the given A.P. sequence is a₁₅ = 33.

Learn more about arithmetic progression here

brainly.com/question/6561461

#SPJ1

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45) Which of the following side lengths forms a unique triangle?
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All answers that are right

select alll legnths that cn make a triangle

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longest side must be less than the sum of the measures of the other 2 sides
in other words, side1+side2>longest side
 
A. no longest side, so this is possible

B. longest is 17, 14+11>17 so it is possible

C. 414 is longest, 109+214<414 so this is NOT possible

D. 8 is longest, 2+7>8 so it is a possible triangle

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3 0
3 years ago
The sum of two integers is 49 and their difference is 9. Find the numbers
Andrews [41]

Answer:

29 and 20 are such integers.

Step-by-step explanation:

Let one of the two integers = m

let other integer  = n

Now, since sum of two integers = 49

⇒   m + n  = 49  ............  (1)

The difference of two integers = 9

⇒    m - n   = 9  ................ (2)

Solving both the equations:

Add equations (1) and (2) , we get

2 m    = 58

or, m  = 58 / 2  = 29

or, m  = 29

So, one of the integers  =  m   =   29

Now, the other integer  is  n  = 49  - m  = 49 - 29  = 20

or, n =  29

Hence, 20 and 29 are such integers.

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