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2 years ago

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A chemist reacted 0. 2 moles sodium benzoate with 0. 25 moles of hydrochloric acid. if she generated 22 g benzoic acid, what was

her percent yield? (mw of benzoic acid = 122. 12 g mol-1)

1 answer:

sesenic [268]2 years ago

7 0

A chemist reacted 0. 2 moles sodium benzoate with 0. 25 moles of hydrochloric acid. if she generated 22 g benzoic acid, the percent yield is 90%.

Reactant + HCl ------ Product

0.2 mol 0.25 22g

mol

Number of moles of reactant = 0.2mol

Molar mass of product = 122.12g

Number of moles of product = given mass/ molar mass

= 22g/ 122.12 g

= 0.180mol

Percent yield = (number of moles of product/ number of moles of reactant) × 100

= (0.180/0.2) × 100

= 90%

Thus we concluded that the percent yield of the given solution is 90%.

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