Answer:
Pressure gas A
using boyles law
= 
V2
V2 = 717ml + 179 ml
= 896ml
∴ = 2.50 × 717ml/896ml
= 2.0 bar
Pressure B
P2 = 4.30 bar× 179ml/896ml
= 0.859bar
ptotal = 
+
= 2.0 bar + 0.859 bar
= 2.859 bar
Explanation: Using Daltons law of partial pressure,the pressure is independently of each other when the gas is exerted.where we can use daltons law to find the pressure of each gas separately when it expands into the total volume in two containers.
Answer:
Decomposition Reaction
Explanation:
If you are referring to what type of reaction that occurred then the answer would be decomposition reaction.
This is a chemical reaction where one reactant is broken down into two or more products.
REACTANT → PRODUCT
AB → A + B
The products can be two or more elements or two or more compounds, depending on what was decomposed.
The net ionic equation is
Ag⁺(aq) +Cl⁻(aq) → AgCl(s)
Explanation
AgNO₃ (aq) + KCl (aq)→ AgCl(s) +KNO₃(aq)
from above molecular equation break all soluble electrolyte into ions
Ag⁺(aq) +NO₃⁻ (aq) + K⁺(aq) +Cl⁻(aq) → AgCl (s) + K⁺(aq) + No₃⁻(aq)
cancel the spectator ions in both side of equation =K⁺ and NO₃⁻ ions
The net ionic equation is therefore
= Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles
moles of O2 is half
so 40.04 x 0.5
20.02moles
grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g
Answer:
Inflamabilidad y características de la llama: el hidrógeno es inflamable en el aire en un amplio rango de concentraciones y arde, en ausencia de impurezas, con una llama casi invisible. Energía de ignición: el hidrógeno puede entrar en ignición con una cantidad de energía muy pequeña.
Explanation:
espero te sirva✍️
