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vodomira [7]
4 years ago
8

Describe how to write the Keq expression for the following reaction. 2NH3(g) 3H2(g) + N2(g)

Chemistry
2 answers:
andrezito [222]4 years ago
7 0

Answer:

Pure solids and pure liquids are not included in the equilibrium constant expression.

Since all reactants and products are gases, they are all included in the equilibrium constant expression.

Write the concentrations of the products in the numerator (top) and the reactants in the denominator of the fraction.

Raise the concentrations to the correct power, based on the coefficients.

Write the expression as

Explanation:

edg2020

included statements

ololo11 [35]4 years ago
3 0

Explanation:

2NH3(g) --> 3H2(g) + N2(g)

The equlibrium constant is the ratio of the concentration of products to that of reactants.

Keq = [Products] / [Reactants]

So to write the expression, we have to identify our reactants and products.

Reactants = NH3

Products = H2 and N2

The coefficients are expressed as powers of the entities in the expression, this leads us to;

[Products] = [H2]² [ N2]

[Reactants] = [NH3]³

Keq = [NH3]³ / [H2]² [ N2]

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