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1 year ago

9

Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.

both -1 and -6 are true solutions. the solution -6 is an extraneous solution. neither -1 nor -6 is a true solution to the equation.

1 answer:

Arada [10]1 year ago

4 0

Answer:

X = 7

Explanation:

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A student mixes two clear liquids together. After a few minutes, a white powdery solid can be seen settling on the bottom of the

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3 years ago

Are two atoms of the same element identical??

Neko [114]

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2 years ago

Which two elements have similar physical and chemical properties?

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Explanation:

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2 years ago

When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the

stepan [7]

<h2> $K_a$ = $\dfrac{[H^{+}] [A^{-}]}{[HA]}$ </h2>

Explanation:

When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

${\displaystyle {\ce {HA$ ⇄ ${H^+}+{A^{-}}} }}$

Here HA is a protonic acid such as acetic acid, $CH_3COOH$

The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.

The acid dissociation constant can be given by -

$K_a$ = $\dfrac{[H^{+}] [A^{-}]}{[HA]}$

The reaction is can also be represented by Bronsted and lowry -

$\\{\displaystyle {\ce {{HA}+ H_2O}$ ⇄ $[H_3O^+] [A^-]$

Then the dissociation constant will be

$K_a$ = $\dfrac{[H_3O^{+}] [A^{-}]}{[HA]}$

Here, $K_a$ is the dissociation constant of an acid.

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Find the pH of a solution whose H concentration is 0.7 x 10-3.

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Answer: pH = 3.15

Explanation: Solved in the attached picture.

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