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2 years ago

What volume of a 0.35M solution of sodium chloride could be formed with 25 grams of NaCl?

Chemistry

1 answer:

Margaret [11]2 years ago

6 0

Answer:

A concentrated solution has a greater amount of dissolved solute than a dilute solution. Explanatio ... More

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Many plants obtain glucose through the process of ___

ryzh [129]

Answer:

Explanation:

8 0

3 years ago

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(4 points) The following lead compound for a pharmaceutical drug contains a rotatable bond. Using the principles of rigidificati

masya89 [10]

Answer:

Explanation:

The solution has been attached

3 0

2 years ago

Chlorine reacts with sodium and with hydrogen.

Sonbull [250]

Answer:

Sodium Chloride has Ionic bond while Hydrogen Chloride has covalent bond.

Explanation:

Na has 11 electrons (2, 8, 1) and need to give away 1 electron to be stable

Cl has 17 electrons ( 2, 8, 7) and needs 1 electron to be stable.

Na transfers 1 electron to CL to form Ionic bond.

While

Hydrogen has 1 electron and shares with Chlorine to be stable.

Covalent bond involves sharing.

3 0

3 years ago

mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of

anygoal [31]

Answer: The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

Explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

$1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol$

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

For nitrogen gas:

Molar mass of nitrogen gas = 28 g/mol

$\text{Moles of nitrogen gas}=\frac{x}{28}mol$

For hydrogen gas:

Molar mass of hydrogen gas = 2 g/mol

$\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol$

Equating the moles of the individual gases to the moles of mixture:

$0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g$

To calculate the mass percentage of substance in mixture we use the equation:

$\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100$

Mass of the mixture = 13.22 g

For nitrogen gas:

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

$\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%$

For hydrogen gas:

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

$\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%$

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0

3 years ago

If 1 mol of XO₂ contains the same number of atoms as 60 g of XOs, what is the molar mass of XO₂?

Lena [83]

Answer:

44 grams/mole

Explanation:

If 1 mol of XO₂ contains the same number of atoms as 60 g of XO3, what is the molar mass of XO₂?

60 grams of XO3 is one mole XO3, since it has the same number of atoms as 1 mole of XO2.

Let c be the molar mass of X. The molar mass of XO3 is comprised of:

X: c

3O: 3 x 16 = 48

Total molar mass of XO3 is = 48 + c

We know that the molar mass of XO3 = 60 g/mole, so:

48 + c = 60 g/mole

c = 12 g/mole

The molar mass of XO2 would be:

1 X = 12

2 O = 32

Molar mass = 44 grams/mole, same as carbon dioxide. Carbon's molar mass is 12 grams.

5 0

2 years ago