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Greeley [361]
2 years ago
13

Im pulling my hair out with this problem my calculator simplified it to

qrt%7B14%7D%7D%7B10%7D" id="TexFormula1" title="\frac{1+/-\sqrt{14}}{10}" alt="\frac{1+/-\sqrt{14}}{10}" align="absmiddle" class="latex-formula">
What am i doing wrong?? :')

Mathematics
2 answers:
blsea [12.9K]2 years ago
7 0

Answer:

-5/3 and -1

Step-by-step explanation:

I am not sure what you mistake is, but here is my solution.  I hope that it helps.  I am sorry that you are frustrated.  We have all been there.

Tamiku [17]2 years ago
6 0

~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -\frac{5}{3} \end{cases}

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Is a scalene triangle a regular polygon
GarryVolchara [31]
No, because all the sides have to be equal 
8 0
3 years ago
Tickets for a play were $2 for each child and $4 for each adult. At one showing of the play, one adult brought 4 children and th
oksano4ka [1.4K]

Answer: 16

Step-by-step explanation:

Tickets for a play were $2 for a child and $4 for an adult.

Tickets price for a child= $2

Tickets price for an adult= $4

One adult brought 4 children. This will give a price of:

(1×4) + (2×4) = 4+8 = $12

The remaining adults brought 2 children each.

Let the remaining adults be y. Each adult will spend:

4+(2×2) = 4+4 = $8

Since there are y adults, it will give 8×y = 8y.

8y + 12 = 60

8y = 60-12

8y = 48

y = 48/8 = 6

The remaining adults are 6. Since we had one adult earlier, total adults will be 7.

To get the number of children that went to the play will be:

(P × number of children) + (price× number of adults) = $60

= (2 × children) + (4 × 7) = $60

= (2 × children) + $28 = $60

= (2 × children) = $60 - $28

= (2 × children) = $32

Children= 32/2

Children= 16

There are 16 children at the play.

3 0
3 years ago
Read 2 more answers
Assume that P(E) = 0.471 and P(F) = 0.595. If E and F are independent, find P(E and F)
dsp73

The value of the probability P(E and F) is 0.2802

<h3>Independent probability</h3>

Events are known to be independent if the occurrence of one does not affect the other.

Given the following parameters

P (E) =0.471

P(F) = 0.595

If E and F are independent, then;

P(E and F) = P(E)P(F)

P(E and F)  = 0.471 * 0.595
P(E and F)  = 0.2802

Hence the value of the probability P(E and F) is 0.2802

Learn more on independent events here: brainly.com/question/1374659

#SPJ1

8 0
2 years ago
I NEED HELP PLZ PLZ PLZ PLZ PLZ DON'T DELETE!
Vaselesa [24]

Answer:

1/100000

Step-by-step explanation:

1/10*1/10*1/1000=1/100*1/1000=1/100000

4 0
3 years ago
6th-grade math DUE IN 5 MIN
Veseljchak [2.6K]

Answer:

272?

Step-by-step explanation:

10 x 8 = 80

12 x 16 = 192

192 + 80 = 272.

Not sure

3 0
3 years ago
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