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Greeley [361]
2 years ago
13

Im pulling my hair out with this problem my calculator simplified it to

qrt%7B14%7D%7D%7B10%7D" id="TexFormula1" title="\frac{1+/-\sqrt{14}}{10}" alt="\frac{1+/-\sqrt{14}}{10}" align="absmiddle" class="latex-formula">
What am i doing wrong?? :')

Mathematics
2 answers:
blsea [12.9K]2 years ago
7 0

Answer:

-5/3 and -1

Step-by-step explanation:

I am not sure what you mistake is, but here is my solution.  I hope that it helps.  I am sorry that you are frustrated.  We have all been there.

Tamiku [17]2 years ago
6 0

~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -\frac{5}{3} \end{cases}

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What is equal to 6(x-4)
nadezda [96]

Answer:

6x - 24

Step-by-step explanation:

6(x-4) .....

Multiply the parentheses by 6:

6x - 6 x 4

Multiply the numbers:

6x - 24

5 0
4 years ago
Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rec
ICE Princess25 [194]

Shawndra is correct

 

She made two statements, and both are true:

 

1. It is not possible to draw a trapezoid that is a rectangle.

This is true because a trapezoid<span> is a quadrilateral that has exactly one pair of parallel sides, whereas a rectangle is a parallelogram (i.e. it has two pairs of parallel sides)</span>

 

2. It is possible to draw a square that is a rectangle.

This is true because a rectangle refers to any parallelogram with right angles. A square is also a parallelogram (has two pairs of opposite sides) with right angles. In fact, all squares are rectangles; only that they are a special kind of rectangle, where all the sides are equal in length.

8 0
4 years ago
Read 2 more answers
Solve the given system of equations2y=x+93x-6y=-15
attashe74 [19]

Answer:

No solutions

Explanation:

The given system of equations is

2y = x + 9

3x - 6y = -15

To solve the system, we first need to solve the first equation for x, so

2y = x + 9

2y - 9 = x + 9 - 9

2y - 9 = x

Then, replace x = 2y - 9 on the second equation

3x - 6y = -15

3(2y - 9) - 6y = -15

3(2y) + 3(-9) - 6y = -15

6y - 27 - 6y = -15

-27 = -15

Since -27 is not equal to -15, we get that this system of equation doesn't have solutions.

5 0
1 year ago
Evaluate the expression 4−(1−4)−2 =
Cloud [144]

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3 0
3 years ago
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Find the exact value of the given expression.<br> sin(2cos^-1(5/13))
xeze [42]

Answer:

+120/169 or -120/169

Step-by-step explanation:

  • let cos^{-1}[\frac{5}{13}  ] = \alpha

where, alpha is some angle that satisfies the assumed condition.

  • so, cos\alpha= 5/13

[ taking cos to the other side  or applying cos on both sides]

  • now, substitute this in the given expression
  • sin(2cos^-1(5/13)) = sin(2\alpha )

as sin\beta =  + or -\sqrt{1-(cos\beta) ^{2}

[by general trigonometry formula: cos^{2}[\beta]  +sin^{2}[\beta]=1]

so if  cos\alpha= 5/13, we can get sin\alpha from the above formula as + or - 12/13

(because, after taking square root on both sides we keep + or -]

  • as, sin2\beta  = 2*sin[\beta ]*cos[\beta ]

[by general trigonometry formula]

  • here, now sin[2\alpha ]=2*(+or- 12/13)*5/13\\

so, the final value can be 120/169 or -120/169.

4 0
3 years ago
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