Im pulling my hair out with this problem my calculator simplified it to
qrt%7B14%7D%7D%7B10%7D" id="TexFormula1" title="\frac{1+/-\sqrt{14}}{10}" alt="\frac{1+/-\sqrt{14}}{10}" align="absmiddle" class="latex-formula">
What am i doing wrong?? :')
What am i doing wrong?? :')
2 answers:
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Answer:
By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that
Step-by-step explanation:
Given that ∠ABC=∠ADC, AD=p and DC=q.
Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles
and given ∠ABC=∠ADB=90°
Hence using AA postulate, ΔABC ≈ ΔADB.
Now we will equate respective side ratios in both triangles.
Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.
Cross multiply
Hence proved.
Answer:
b. the area to the right of 2
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.
In this problem:
Percentage who did better:
P(Z > 2), which is the area to the right of 2.