1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leya [2.2K]
2 years ago
13

A transverse travelling sinusoidal wave on a string has a frequency of 100hz a wavelength of 0.040m and an amplitude of 2mm the

max velocity of any point on the string is
Physics
1 answer:
kirill115 [55]2 years ago
8 0

Vmax = 1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

Maximum velocity is given by,

Vmax = Aω

where,

V = velocity

A = amplitude

ω = angular displacement

ω is given by,

ω = 2\pif

where f = frequency

ω = 2\pif

   = 2*3.147*100

   = 629.4 rad

A = amplitude = 2mm

Vmax = Aω

         = 2 ×10^{-3} × 629.4

         = 1.258 m/s

Maximum velocity = Vmax =  1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

<h3>What is meant by sinusoidal wave?</h3>
  • The curve representing a smooth repeated oscillation is known as a sine wave or sinusoidal wave.
  • The sine wave is "the wave form in which the amplitude is always proportional to sine of its displacement angle at every point in time," according to the definition.
  • Sine waves can be added together to create any wave.

<h3>What makes a wave a sinusoidal wave?</h3>
  • The waveform shape created by our straightforward single loop generator is then frequently referred to as a sine wave since it is seen to have a sinusoidal shape.
  • Because it is based on the trigonometric sine function used in mathematics (x(t) = Amax. sin), this sort of waveform is known as a sine wave.

To learn more about sinusoidal wave visit:

brainly.com/question/14695510

#SPJ4

You might be interested in
Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t
ziro4ka [17]

Answer:

(a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

Explanation:

Given that,

Rotation = 20.0 times

Time = 5.00 sec

We need to calculate the angular frequency

Using formula of angular frequency

\omega_{i}=20\times\dfrac{2\pi}{T}

put the value into the formula

\omega_{i}=20\times\dfrac{2\pi}{5.00}

\omega_{i}=8.00\pi

We need to calculate the angular displacement

Using formula of  angular displacement

\theta=6\times2\pi=12\pi

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}^2-\omega_{i}^2=2\alpha\times\theta

0-64\pi^2=2\times12\pi\times\alpha

\alpha=-\dfrac{64\pi^2}{24\pi}

\alpha=-8.3\ rad/s^2

Negative sign shows the opposite direction of the motion.

The acceleration is 8.3 rad/s².

We need to calculate the time

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha\times t

0-8\pi=-8.3t

t=\dfrac{8\pi}{8.3}

t=3.0\ sec

The time is 3.0 sec.

Hence, (a). The acceleration is 8.3 rad/s².

(b). The time is 3.0 sec.

4 0
3 years ago
A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im
vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}

\dfrac{1}{v}=\dfrac{7}{690}

v=98.57\ cm

We need to calculate the height of the image

Using formula of height

\dfrac{h'}{h}=\dfrac{-v}{u}

Where, h' = height of image

h = height of object

\dfrac{h'}{4}=\dfrac{-98.57}{-30}

h'=\dfrac{98.57\times4}{30}

h'=13.14\ cm

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}

\dfrac{1}{v}=-\dfrac{10}{299}

v=-29.9\ cm

We need to calculate the height of the image

\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}

h=-\dfrac{29.9\times4}{13.0}

h=-9.2\ cm

The image is virtual and erect.

Hence, This is required solution.

6 0
3 years ago
Which is a good example of a contact force?
lions [1.4K]
A ball hitting a ball so D
7 0
4 years ago
Read 2 more answers
10.What is the Kinetic Energy of a 150 kg object that is moving with a speed<br> of 15 m/s? (7b)
madam [21]
KE=1/2 mv^2
=1/2(150kg)(15m/s)^2
=16875 kgms^-2
4 0
4 years ago
The magnitude, M, of an earthquake is represented by the equation M=23logEE0 where E is the amount of energy released by the ear
vfiekz [6]

Answer:

The amount of energy released by the earthquake in joules is 4.4×10^12 J.

Explanation:

As, we have given the magnitude,

M = 2/3 Log E/Eo

where E is the amount of energy released by the earthquake in joules and Eo=10^4.4 is the assigned minimal measure released by an earthquake.

As, the magnitude is given which is 5.5 then put it in the above equation,

5.5 = 2/3 Log E/Eo

Log E/Eo = 5.5×3 / 2

Log E/Eo = 8.25

Now, we will find the amount of energy released by an earthquake:

Log E/Eo = 8.25

Taking antilog,

E/Eo = 10^8.25

But Eo is given which is Eo = 10^4.4

E/(10^4.4) = 10^8.25

E = 10^8.25 × 10^4.4

E = 4.4×10^12 J.

8 0
4 years ago
Other questions:
  • Is smoke diffusion??
    15·2 answers
  • Give main forms before and after for the following energy transformations: A gasoline engine.
    15·1 answer
  • Which transformation could take place at the anode of an electrochemical cell?
    11·1 answer
  • One 10.0 amp resistor is wired in a series with two 10.0 amp resistors in parallel. A 45.0 C battery supplies power to the circu
    7·1 answer
  • A ball vibrates back and forth from the free end of an ideal spring having a force constant (spring constant) of 20 N/m. If the
    15·1 answer
  • what is the distance between a point on one wave and the same point on the next cycle of the wave called
    9·1 answer
  • 6. Dan wants to create acceleration. He
    12·1 answer
  • Describe the laws of liquid pressure and explain the term fluid. (Please try to give the correct answer 'coz it's urgent!)​
    10·1 answer
  • What is the weight of a 15 kg object
    7·1 answer
  • A 1500-kg car accelerates from 0 to 25 m/s in 7.0 s. What is the average power delivered by the engine (1 hp
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!