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mylen [45]
3 years ago
11

Which transformation could take place at the anode of an electrochemical cell?

Physics
1 answer:
erica [24]3 years ago
7 0
As I found out the choices for your question which are: 

<span>A) F2 to F-
B) Cr2O7²- → Cr2+ 
C) O2 to H2O
D) HAsO2 to As
</span>
Unfortunately, the answer does not belong to the choices provided. In fact, it is the oxidation half-reaction that occurs at the anode of an electrode for it to transform chemical energy to consumable electrical energy.
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If the same force is applied to an object with a large mass it will have a blank acceleration
kati45 [8]

Answer:

If the same force is applied to an object with a large mass it will have a <u>smaller (lesser) </u>acceleration

Explanation:

force and mass are inversely proportional. force and acceleration are directly proportional. which means greater mass have smaller acceleration and smaller mass has greater acceleration. this is due to newtons second law of motion.

3 0
3 years ago
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If a 50-kg Person is running at a rate of 2m/s, the person's momentum is _____ kg• m/s.
sergiy2304 [10]

Answer:

100

Explanation:

Use equation p=mv

p=(50kg)(2m/s)= 100

8 0
3 years ago
You set a small eraser at a distance of 0.27 m from the center of a turntable you find in the attic and establish that when the
Licemer1 [7]

Answer with Explanation:

We are given that

Distance,r=0.27 m

Tangential speed=v=0.49 m/s

a.Angular speed ,\omega=\frac{v}{r}

Using the formula

\omega=\frac{0.49}{0.27}=1.8 rad/s

\omega=\frac{2\pi}{T}

T=\frac{2\pi}{\omega}

Time period,T=\frac{2\pi}{1.8}=3.49 s

b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m

c.Maximum speed,V_{max}=0.49 m/s

d.Maximum acceleration=a=r\omega^2=0.27(1.8)^2=0.87 m/s^2

5 0
4 years ago
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Can someone help check question 2 I don’t think part 2 is right?!
Alisiya [41]
Your answer for question two is right
4 0
3 years ago
A 0.45 kg ball is moving horizontally with a speed of 5.3 m/s when it strikes a vertical wall. The ball rebounds with a speed of
qaws [65]

Answer:

1.31Kgms-1

Explanation:

∆p = m∆v

Where:

∆p= change in momentum

m= mass of the ball

∆v= change in velocity of the ball= (5.3-2.4)= 2.9ms-1

Therefore, substituting appropriately with the values above:

∆p= 0.45×2.9= 1.31Kgms-1

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4 years ago
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