Answer:
n = 1,875
Explanation:
The speed of light in vacuum is constant (c) and in a material medium it is
v = d / t
The refractive index of a material is defined by
n = c / v
Let's look for the speed of light in the material, in general the length that light travels is known, this value is high, x = 1, when we place a block on the road, a small amount is lengthened by the length of the block, which in general is despised
These measurements are made on a digital oscilloscope that allows to stop the signals and measure their differences, that is, the zero is taken when the first ray arrives and the time for the second ray is measured,
v = d / t
v = 1 / 6.25 10⁻⁹
v = 1.6 10⁸ m / s
we calculate the refractive index
n = 3 10⁸ / 1.6 10⁸
n = 1,875
- Some people view bacteria specimens with a 100x objective lens in order to see the smallest details.
- Others may use a 10x objective lens for more general purposes, such as examining stained slides or pictures.
- And still others may use a 40x objective lens to gain maximum resolution when viewing images of thick samples.
It is important to choose the appropriate magnification for your needs so that you can properly examine the specimen under study.
<h3>Why is the 100x objective lens necessary to see bacteria?</h3>
- Bacteria must, of course, be viewed at the maximum magnification and resolution possible because to their small size.
- Due to optical restrictions, this is approximately 1000x in a light microscope.
- To improve resolution, the oil immersion method is performed. This calls for a unique 100x objective.
To learn more about bacterial specimen, visit:
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Answer:
T=0.827s
Explanation:
The period of a spring can be calculated with the equation
But we know as well that w is given by,
Replacing,
So we have that
Answer:
The acceleration of the cart is 1.0 m\s^2 in the negative direction.
Explanation:
Using the equation of motion:
Vf^2 = Vi^2 + 2*a*x
2*a*x = Vf^2 - Vi^2
a = (Vf^2 - Vi^2)/ 2*x
Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.
Let x = Xf -Xi
Where Xf is the final position of the cart and Xi the initial position of the cart.
x = 12.5 - 0
x = 12.5
The cart comes to a stop before changing direction
Vf = 0 m/s
a = (0^2 - 5^2)/ 2*12.5
a = - 1 m/s^2
The cart is decelerating
Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.
