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Furkat [3]
3 years ago
12

6. Dan wants to create acceleration. He

Physics
1 answer:
kiruha [24]3 years ago
8 0

d. Maintain constant velocity

Explanation:

A constant velocity leads to no acceleration.

Acceleration is defined as the change in velocity with time:

  Acceleration = \frac{change in velocity}{time taken}

If there is no change in velocity i.e constant velocity.

At constant velocity, the change in velocity is 0.

 If we put zero in the equation above, we will obtain an acceleration value of 0.

Learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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How fast would the car need to go to double its kinetic energy?
boyakko [2]

Answer:

v_{f} = \sqrt{2}\cdot v_{o}

Explanation:

Let consider a car travelling at a speed v_{o}. The ratio of final kinetic energy to initial kinetic energy:

\frac{\frac{1}{2}\cdot m \cdot v^{2}_{f} }{\frac{1}{2}\cdot m \cdot v^{2}_{o}} = 2

\frac{v_{f}}{v_{o}} = \sqrt{2}

The final speed is:

v_{f} = \sqrt{2}\cdot v_{o}

3 0
3 years ago
Read 2 more answers
Consider a semi-spherical bowl machined out of wood (A drawing of a semi-spherical bowl can be found in UNIT- 4 Introduction, so
Mrrafil [7]

Answer:

The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)

Explanation:

The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.

a) Outer semi-sphere:

A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²

b) Inner semi-sphere:

A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²

c) Edge (Ring):

A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²

Therefore, the total surface area of the bowl is given by:

A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)

Changing units to m², as required in the problem, we get:

A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)

5 0
3 years ago
How do you calculate acceleration
AfilCa [17]
A=f/m
Example a=10/2
A=5
7 0
3 years ago
Read 2 more answers
I beggggg youu to solve this for me, I'm giving you 60 POINTS !!!
djyliett [7]

Answer:

but where is the question ?

Explanation:

<em>hope</em><em> it</em><em> </em><em>works</em><em> out</em>

6 0
3 years ago
Read 2 more answers
(a) What is the potential between two points situated 10 cm and 20 cm from a 3.0-μC point charge? (b) To what location should th
julia-pushkina [17]

Answer:

(a) 135 kV

(b) The charge chould be moved to infinity

Explanation:

(a)

The potential at a distance of <em>r</em> from a point charge, <em>Q</em>, is given by

V = -\dfrac{kQ}{r}

where k = 9\times 10^9 \text{ F/m}

Difference in potential between the points is

kQ\left[-\dfrac{1}{0.2\text{ m}} -\left( -\dfrac{1}{0.1\text{ m}}\right)\right] = \dfrac{kQ}{0.2\text{ m}} = \dfrac{9\times10^9\text{ F/m}\times3\times10^{-6}\text{ C}}{0.2\text{ m}}

PD = 135\times 10^3\text{ V} = 135\text{ kV}

(b)

If this potential difference is increased by a factor of 2, then the new pd = 135 kV × 2 = 270 kV. Let the distance of the new location be <em>x</em>.

270\times10^3 = kQ\left[-\dfrac{1}{x}-\left(-\dfrac{1}{0.1\text{ m}}\right)\right]

10 - \dfrac{1}{x} = \dfrac{270000}{9\times10^9\times3\times10^{-6}} = 10

\dfrac{1}{x} = 0

x = \infty

The charge chould be moved to infinity

7 0
3 years ago
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