Question

In Triangle 2, b=10 in, a=14 in, and theta=65 degrees solve for c, a, and B.

Answer 1

The length of c is c = 13.3, and the angle measures are A = 17.7 and B = 97.3

How to determine the missing sides and angles of the triangle?

From the question, we have the given parameters to be:

b = 10 inches

a = 14 inches

<C = 65 degrees

To calculate the length of c, we use the following equation of law of cosine

c^2 = a^2 + b^2 - 2 * a * b * cos(C)

Substitute the known values in the above equation

c^2 = 14^2 + 10^2 - 2 * 10 * 14 * cos(65 degrees)

Evaluate cos(65 degrees)

c^2 = 14^2 + 10^2 - 2 * 10 * 14 * 0.4226

Evaluate the exponent

c^2 = 196 + 100 - 2 * 10 * 14 * 0.4226

Evaluate the product

c^2 = 196 + 100 - 118.328

Evaluate the sum and the difference

c^2 = 177.672

Take the square root of both sides

c = 13.3

To calculate the angle measure of A, we use the following equation of law of sine

a/sin(A) = c/sin(C)

This gives

14/sin(A) = 13.3/sin(65)

This gives

14/sin(A) = 14.7

Rewrite as:

sin(A)  = 14/14.7

Evaluate the quotient

sin(A)  = 0.9524

Take the arc sin of both sides

A = 17.7

Lastly, we have

B = 180 - A - C

This gives

B = 180 - 17.7 - 65

Evaluate

B = 97.3

Hence, the length of c is c = 13.3, and the angle measures are A = 17.7 and B = 97.3

Read more about law of cosines and sines at:

brainly.com/question/4372174

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