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Strike441 [17]
3 years ago
13

One half of the total cost

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0
You divid it by two my dude
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Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi
stealth61 [152]
Applying our power rule gets us our first derivative,

\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}

simplifying a little bit,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

looking for critical points,

\rm 0=2x^{-2/3}+4x^{1/3}

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

0=2x^{-2/3}\left(1+2x\right)

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

and take our second derivative.

\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}

Looking for inflection points,

\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}

Again, pulling out the smaller power of x, and fractional part,

\rm 0=-\frac43x^{-5/3}\left(1-x\right)

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.
8 0
3 years ago
Estimate the quotient for 49 / 311
Makovka662 [10]
To get a close estimate, we can round 49 up to 50 and 311 down to 300, obtaining an estimate of 50/300 = 1/6, or 0.1666... as a repeating decimal. That decimal approximation is a little less than one hundredth away from the actual decimal approximation of ≈ 0.1576
4 0
3 years ago
Read 2 more answers
Help I can’t solve this at all
qwelly [4]
<h2>Answer: </h2>

We know that,

  • Length of arc = 2πrθ/360

Length of arc = 2 × 3.14 × 6 × 45/360

Length of arc = 6.28 × 3/4

= 18.84/4

= 4.71units.

8 0
3 years ago
Which two lines below are perpendicular lines?
Naily [24]

Answer:

You said never mind, but I really like your username :)

Step-by-step explanation:

6 0
2 years ago
If x-13 = k and k = 3, what is the value of x?
77julia77 [94]

Answer:

x = 16

16 - 13 = 3

***brainliest please

Step-by-step explanation:

5 0
3 years ago
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