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2 years ago

Hello I need help in this

Mathematics

1 answer:

maw [93]2 years ago

5 0

There are 22 books total on the shelf and 9 of them are biographical books so the probability is 9/22

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What is 65% written as a decimal?<br> A. 0.065<br> B. 0.65<br> C. 6.5<br> D. 65

MrRa [10]

Answer:

b.0.65

Step-by-step explanation:

i think it is I'm sorry if it's not

6 0

3 years ago

Read 2 more answers

Which are the solutions of the quadratic equation x2 =-5-3

alexdok [17]

Answer: x = 2 • ± √2 = ± 2.8284

Step-by-step explanation:

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 8 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step 1 :

x2 - 8 = 0

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : x2-8 = 0

Add 8 to both sides of the equation :

x2 = 8

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

x = ± √ 8

Can √ 8 be simplified ?

Yes! The prime factorization of 8 is

2•2•2

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 8 = √ 2•2•2 =

± 2 • √ 2

The equation has two real solutions

These solutions are x = 2 • ± √2 = ± 2.8284

Two solutions were found :

x = 2 • ± √2 = ± 2.8284

Not sure what you need help with, but I hope I helped you somehow.

5 0

2 years ago

The signs of the product of 263 and 0 is

Mashcka [7]

The answer to the question is 0

6 0

3 years ago

Read 2 more answers

Try to simplify 72/6+85/6

Reil [10]

72/6+ 85/6
= (72+ 85)/6
= 157/6
= (156+1)/ 6
= 156/6+ 1/6
= 26+ 1/6
= 26 1/6

The final answer is 26 1/6~

4 0

3 years ago

Read 2 more answers

1.) Find the value of the discriminant and the the number of real solutions of

ruslelena [56]

Hi there!

When we have an equation standard form...
$a {x}^{2} + bx + c = 0$
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

$( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36$

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.

${4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0$

D = 0 and therefore we have one real solution.

~ Hope this helps you.

4 0

2 years ago

Read 2 more answers

Hello I need help in this​

Hello I need help in this