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Rufina [12.5K]
2 years ago
5

Wordy LCM & HCF. There are three 50m swimming lanes. Those in lane A set

Mathematics
1 answer:
MatroZZZ [7]2 years ago
3 0
In 30 minutes
you multiply the three lane times together and that is the answer
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Square ABCD is shown below.
valentina_108 [34]

Answer:

35 is the length of BE

Step-by-step explanation:

2(2x + 5) = 8x - 50

4x + 10 = 8x -50

10+50 = 8x-4x

60= 4x

15 = x

2x + 5 = length of BE equal to length of DE

2(15) +5 = BE

30 +5

35 is the length of BE

6 0
3 years ago
Can somebody PLEASE HELP ME
svet-max [94.6K]

Answer:

150.796π square meters

maybe!

Step-by-step explanation:

4 0
3 years ago
Cameron runs 2.4 miles 3 days a week. How many miles does he run total in one week?
Ainat [17]

Answer:

5.6

Step-by-step explanation:

2.4 / 3 = x / 7

2.4 x 7 = 16.8

16.8 ÷ 3 = 5.6

5 0
3 years ago
Read 2 more answers
Simplify.<br> 3/3-n - n/n-3
Black_prince [1.1K]
\frac{3}{3-n}- \frac{n}{n-3}= \frac{3}{3-n}-(- \frac{n}{3-n})= \frac{3}{3-n}+\frac{n}{3-n}= \frac{3+n}{3-n}
8 0
3 years ago
The U.S. Bureau of Labor Statistics reports that of persons who usually work full-time, the average number of hours worked per w
alukav5142 [94]

Answer:

The standard deviation of number of hours worked per week for these workers is 3.91.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem we have that:

The average number of hours worked per week is 43.4, so \mu = 43.4.

Suppose 12% of these workers work more than 48 hours. Based on this percentage, what is the standard deviation of number of hours worked per week for these workers.

This means that the Z score of X = 48 has a pvalue of 0.88. This is Z between 1.17 and 1.18. So we use Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{48 - 43.4}{\sigma}

1.175\sigma = 4.6

\sigma = \frac{4.6}{1.175}

\sigma = 3.91

The standard deviation of number of hours worked per week for these workers is 3.91.

6 0
3 years ago
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