Answer:
a) Arithmetic
b) 22.5
c) 4.5
d) a_n = 4.5 + 4.5(n - 1)
e) a_15 = 67.5
Step-by-step explanation:
a) Subtract one term by the term right before it, and the difference will be the common difference.
9 - 4.5 = 4.5
13.5 - 9 = 4.5
18 - 13.5 = 4.5
Therefore, the common difference is 4.5.
b) Since the common difference is 4.5, add 4.5 to the 18 (which was the last value given). The result is 22.5.
c) We have already figured out that the common difference is 4.5.
d) The explicit formula would be a_n = a1 + d(n - 1). The first term is 4.5 and d is also 4.5, so the explicit formula is a_n = 4.5 + 4.5(n-1).
e) Plug 15 into our explicit formula for n. a_15 = 4.5 + 4.5(14). The result is 67.5.
Answer:
least to greatest: {61, 61, 61, 178, 179}
Step-by-step explanation:
If the third-largest angle is 61°, the smallest three angles cannot be larger than 183°. Since the total of all angles must be 540°, and the total of the largest two cannot be greater than 179°×2 = 358°, the sum of the smallest three must be at least 540° -358° = 182°.
So, the possible sets of angles with the smallest 3 totaling 182° or 183° are (in degrees) ...
{60, 61, 61, 179, 179} . . . . two modes
(61, 61, 61, 178, 179} . . . . . one mode -- the set you're looking for
check the picture below.
now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.
incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.
so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

so that's the area of the trapezoid, now let's get the area of the triangle.

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?
