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olya-2409 [2.1K]
3 years ago
11

Chelsea had $71.18 she bought a new pair of glasses for $59.95 can she buy a case that costs $12.95​

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
4 0

No, because she only has $11.23 left.

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PLEASE HELP! WILL MARK BRAINLIEST!! :D
netineya [11]

Hope this helps

Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.

6 0
3 years ago
Factor the polynomial expression x4 + 18x2 + 81
Akimi4 [234]

Answer: (x^2+9)^2

Step-by-step explanation:

Rewrite it in the form a^2+2ab+b^2 , where a=x^2 and b=9.

(x^2)^2+2(x^2)(9)+9^2

Use Square of Sum: (a+b)^2= a^2+2ab+b^2

(x^2+9)^2

4 0
3 years ago
Find the length of side x in simplest radical form with a rational denominator<br><br>​
HACTEHA [7]

Answer:

x =  \sqrt{2}

Step-by-step explanation:

\tan 30 \degree =  \frac{x}{ \sqrt{6} }  \\  \\  \frac{1}{ \sqrt{3} } =  \frac{x}{ \sqrt{6} }    \\  \\ x =  \frac{ \sqrt{6} }{ \sqrt{3} }  \\  \\ x = \frac{ \:  \sqrt{3}  \times  \sqrt{2} }{ \sqrt{3} }  \\  \\ x =  \sqrt{2}

5 0
3 years ago
1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
Ahmed wrote the two expressions below.
Vsevolod [243]
Put an equal sign between the two expressions, and solve for x
3 0
4 years ago
Read 2 more answers
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