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LenKa [72]
2 years ago
6

What would you do if a bunsen burner caught fire at the base of the burner, by the flame adjusting valve?

Chemistry
1 answer:
Andre45 [30]2 years ago
5 0

We should Turn off the Bunsen burner, move away any other combustible materials, Smother the fire with a watch glass or damp cloth and notify the teacher immediately.

The use of Bunsen burners poses a fire risk. They generate an open flame and burn at a high temperature, which increases the risk of an accident. It is crucial that the following rules are followed for everyone working in a laboratory's safety and convenience. In the event of a fire, sound the nearest fire alarm pull station, alert all lab staff, and leave the area immediately.

Learn more about Bunsen burner here-

brainly.com/question/743920

#SPJ4

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Which of the following is true about magnets? SELECT AN ANSWER
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D is the answer you’re welcome
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3 years ago
1. Does the temperature rise or drop when you mix vinegar and baking soda.
Viktor [21]

Answer:

Yes

Explanation:

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3 0
3 years ago
Calculate δg∘rxn and e∘cell for a redox reaction with n = 3 that has an equilibrium constant of k = 4.4×10−2. you may want to re
lapo4ka [179]
a) First, to get ΔG°rxn we have to use this formula when:

ΔG° = - RT ㏑ K 

when ΔG° is Gibbs free energy 

and R is the constant = 8.314 J/mol K

and T is the temperature in Kelvin = 25 °C+ 273 =  298 K 

and when K = 4.4 x 10^-2

so, by substitution:

ΔG°= - 8.314 * 298 *㏑(4.4 x 10^-2)

      = -7739 J  = -7.7 KJ


b) then, to get E
° cell for a redox reaction we have to use this formula:

ΔE° Cell = (RT / nF) ㏑K

when R is a constant = 8.314 J/molK

and T is the temperature in Kelvin = 25°C + 273 = 298 K

and n = no.of moles of e- from the balanced redox reaction= 3

and F is Faraday constant = 96485 C/mol

and K = 4.4 x 10^-2

so, by substitution:

∴ ΔE° cell = (8.314 * 298 / 3* 96485) *㏑(4.4 x 10^-2)

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3 years ago
Write the mole ratios of (2ca+o2➡2cao)
tresset_1 [31]
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Hope this helped!!
6 0
3 years ago
Read 2 more answers
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kicyunya [14]

Answer:

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I hope it's helpful!

6 0
3 years ago
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