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vagabundo [1.1K]
3 years ago
14

Write the mole ratios of (2ca+o2➡2cao)

Chemistry
2 answers:
tresset_1 [31]3 years ago
6 0
N(Ca)/2 = n(O)/1 = n(CaO)/2

The calcium and the Calcium Oxide are divided by 2 because of their coefficients
there is no number in front of the oxygen so it is over one.
Hope this helped!!
Svetach [21]3 years ago
5 0

Answer:

This question is incomplete.

Explanation:

Mole ratio is the ratio used to determine the equivalent of two substances (in moles) in a chemical reaction. Only the <u>number of moles</u> of a substance involved in a chemical reaction is considered in mole ratio. Also, the reaction for which mole ratio is to be considered must be balanced.

The interpretation of the equation in the question is that calcium (Ca) and oxygen (O₂) react in the ratio 2:1 to form calcium oxide (CaO).

It can also be said that 2 moles of Ca will be needed in the production of 2 moles of CaO. Hence the mole ratio between the two substances is 2:2.

The mole ratio between O₂ and CaO is 1:2 since 1 mole of O₂ was needed to produce 2 moles of CaO

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7 0
2 years ago
Nitrous oxide (n2o), or laughing gas, is commonly used as an anesthetic in dentistry and surgery. how many moles are present in
Gelneren [198K]

Answer is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.

V(N₂O) = 8.4 L.

V(N₂O) = n(N₂O) · Vm.

Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.

n(N₂O) = 8.4 L ÷ 22.4 L/mol.

n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>

5 0
3 years ago
Gu
Andrei [34K]

According of Dalton's law of Partial pressure, the total pressure of a mixture of gases is the sum of the partial pressures of the individual vases in the mixture.

Hence;

The for hydrogen collected over water, we have a mixture of hydrogen gas and water vapour.

Total pressure = pressure of hydrogen gas + vapour pressure of water

Pressure of hydrogen gas = Total pressure - vapour pressure of water

Pressure of hydrogen gas = 636 mmHg - 28.3 mmHg

Pressure of hydrogen gas = 607.7 mmHg

7 0
2 years ago
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
3 years ago
Which is an example of genetic engineering?
lesya692 [45]

Answer:

C. Golden rice enriched with vitamin A

4 0
3 years ago
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