- NH₃: Hydrogen bonds;
- CCl₄: London Dispersion Forces; (a.k.a. Induced dipole)
- HCl: Dipole-dipole Interactions.
<h3>Explanation</h3>
Relative strength of intermolecular forces in small molecules:
Hydrogen bonds > Dipole-dipole interactions > London DIspersion Forces.
It takes two conditions for molecules in a substance to form <em>hydrogen bonds</em>.
- They shall contain at least one of the three bonds: H-F, O-H, or N-H.
- They shall contain at least one lone pair of electrons.
NH₃ contains N-H bonds. The central nitrogen atom in an NH₃ molecule has one lone pair of electrons. NH₃ meets both conditions; it is capable of forming hydrogen bonds.
CCl₄ molecules are nonpolar. The molecule has a tetrahedral geometry. Dipole from the polar C-Cl bonds cancel out due to symmetry. The molecule is nonpolar overall. As a result, only London Dispersion Force is possible between CCl₄ molecules.
HCl molecules are polar. The H-Cl bond is fairly polar. The HCl molecule is asymmetric, such that the dipole won't cancel out. The molecule is overall polar. Both dipole-dipole interactions and London Dispersion Force are possible between HCl molecules. However, dipole-dipole interactions are most predominant among the two.
alpha decay is an emission of ₂⁴He
nucleus. If an element undergoes an alpha decay, the mass of the daughter
nucleus formed is reduced by 4 compared to mass of parent atom and atomic
number is reduced by 2 compared to atomic number of parent atom.
Let's assume that the parent atom is X, atomic number is z and mass number is A. Then the formed daughter nucleus, Y should have atomic number as z-2 and mass number as A-4.
The equation is
(z) (A)X → ₂⁴α + (z-2)(A-4)Y
Example:
₉₄²³⁹Pu → ₂⁴α + ₉₂<span>²³⁵U</span>
Answer:
Wetlands prevent flooding by temporarily storing and slowly releasing stormwater. Wetlands also reduce water flow, thus allowing sediments and associated pollutants to settle out. Beneficial microor- ganisms (called biofilm) live on wetland plants and process some forms of pollution.
Explanation:
I am sorry i wish i could help you but i dont know the answer either.
