Answer:
The rocket would be in the air for 8.125 seconds after launch.
Step-by-step explanation:
Given that the height of the rocket, h = 260t - 16.
To determine how long the rocket would be in the air, differentiate h totally with respect to t.
So that, total derivative of h is given as;
=
0 = 260 - 16 x 2t
= 260 - 32t
0 = 260 - 32t
32t = 260
t =
= 8.125
t= 8.125 seconds
The rocket would be in the air for 8.125 seconds after launch.
see the attached figure to better understand the problem
Step 1
<u>Find the value of c</u>
we know that
Applying the Pythagorean Theorem
we have
substitute the values in the formula
Step 2
<u>Find the value of angle A (α)</u>
we know that
in the right triangle ABC
Step 3
<u>Find the angle B (β)</u>
we know that
in the right triangle ABC
angle A and angle B are complementary angles
so
A+B=90
solve for B
B=90-A-------> B=90-60.48-----> B=29.52°
therefore
<u>the answers are</u>
a) the measure of side c is 580.36 mm
b) the measure of the angle α is 60.48°
c) the measure of the angle β is 29.52°
