The number of different dinner combinations for each student that are possible is 24
<h3>How many different dinner combinations for each student are possible?</h3>
The given parameters are:
Entree choices = 3
Side dish = 4
Beverage = 2
The number of different dinner combinations for each student that are possible is
Combination = Entree * Side dish * Beverage
This gives
Combination = 3 * 4 * 2
Evaluate
Combination = 24
Hence, the number of different dinner combinations for each student that are possible is 24
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The constant money u get every 1 hour
Answer:
Number of shopper buy from sale [3,000shopper] = 600 (Approx.)
Step-by-step explanation:
Given:
Number of shopper in mall = 60
Number of shopper buy from sale = 12
Find:
Number of shopper buy from sale if total number number of shopper are 3,000
Computation:
Number of shopper buy from sale [3,000shopper] = 3000[Number of shopper buy from sale/Number of shopper in mall]
Number of shopper buy from sale [3,000shopper] = 3000[12 / 60]
Number of shopper buy from sale [3,000shopper] = 3000[1/5]
Number of shopper buy from sale [3,000shopper] = 600 (Approx.)
Each pound cost $3.32
p pounds would cost = p*3.32 = 3.32p
Total cost C = $3.32p
I hope this explains it.
