Question

Please help I’ll mark you as brainliest if correct!

Answer 1

Answer: 1, 8, 3

Step-by-step explanation: +7 jumps.

2 + 7 = 9

9 + 7 = 16 ..... In traditional clock 16 is 4 O'clock.

4 + 7 = 11

11 + 7 = 18 ..... In traditional clock 18 is 6 O'clock.

6 + 7 = 13 ..... In traditional clock 13 is 1 O'clock.

now: next three terms in order are

1 + 7 = 8

8 + 7 = 15 ..... In traditional clock 15 is 3 O'clock.

3 + 7 = 10

The next three terms are: 1,8,3.

2, 9, 4, 11, 6, 1, 8, 3.

Answer 2

Answer:

  ..., 1, 8, 3

Step-by-step explanation:

You want the sequence of clock face numbers that starts 2, 9, 4, 11, 6, ....

Clock face sequence

The numbers in the given sequence are each 7 hours after the one before. 7 hours after a given hour is the same as 5 hours before on a 12-hour clock.

Continuing the sequence by adding 7 or -5 to the previous value to keep within the range [1, 12], we get ...

  2, 9, 4, 11, 6, 1, 8, 3, 10, 5, 12, 7, 2 (and repeats from here)

The next three numbers in the sequence are 1, 8, 3.

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Additional comment

We have described the sequence as the function ...

  $f(1)=2\\\\f(n)=\begin{cases}f(n-1)+7&\text{for }f(n-1) < 6\\f(n-1)-5&\text{for }f(n-1)\ge 6\end{cases}$

The sequence can also be described by the explicit function ...

  $f(n)=1+\!\!\!\mod\!(7n+6,12)$