The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
Answer:
it would be 0.3 with bar notation
Step-by-step explanation:
Let's say that B makes $100.
Then A makes $75.
So, your question then becomes 100 is what percent of 75?
This can be solved by setting up the proportion 100 / 75 = x / 100
75x = 10000
x = 133.3
So, B's income is 33.3% more than A's income.
Y is greater than or equal to five
Answer:
4x-5y=3
-3=4x-5y
Step-by-step explanation:
4x-5y = 3
4x-5y = -3
both statements have different answers but has the same problem making the statement x=x and 0=0 making it have no solution
