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2 years ago

two coils close to each other have a mutual inductance of 32 mh. if the current in one coil decays according to , where i0

Physics

1 answer:

Harlamova29_29 [7]2 years ago

3 0

The EMF induced in the second coil is 43 Volts.

Michael Faraday was the first to discover electromagnetic induction back in the 1830s. Faraday discovered that moving a permanent magnet in and out of a coil or a single loop of wire caused an electromotive force, or EMF—otherwise known as a voltage—to be produced.

Changing magnetic flux results in varied currents flowing through the coil, which in turn generates its own magnetic field. This self-induced EMF opposes the change that is creating it, and the stronger the opposing EMF is, the faster the rate at which the current is changing. According to Lenz's law, this self-induced EMF will oppose the change in current in the coil, and because of its orientation, it is typically referred to as a back-EMF.

To learn more about EMF please visit-

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A satellite has a mass of 5850 kg and is in a circular orbit 4.1 x10 to the 5th power m above the surface of a planet. The perio

koban [17]

Answer:

W = 24.28 kN

Explanation:

given,

Mass of satellite = 5850 Kg

height , h = 4.1 x 10⁵ m

Radius of planet = 4.15 x 10⁶ m

Time period = 2 h

= 2 x 3600 = 7200 s

Time period of satellite

$T = \dfrac{2\pi}{R}\sqrt{\dfrac{(R+h)^3}{g}}$

R is the radius of planet

h is the height of satellite

$T^2 = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{g}}$

now calculation of acceleration due to gravity

$g = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{T^2}}$

$g = \dfrac{4\pi^2}{(4.15\times 10^6)^2}\ {\dfrac{(4.15\times 10^6+4.1\times 10^5)^3}{(7200)^2}}$

g = 4.15 m/s²

True weight of satellite

W = m g

W = 5850 x 4.15

W = 24277.5 N

W = 24.28 kN

True weight of the satellite is W = 24.28 kN

8 0

3 years ago

A 0.366 kg metal cylinder is placed inside the top of a plastic tube, the lower end of which is sealed off by an adjustable plun

DochEvi [55]

Answer:

$a = 32.6 m/s^2$

Explanation:

As we know that pressure between the cylinder and plunger is increased by 1.59 times

So this will make a net force upwards on the cylinder which is given as

$F = \Delta P A$

now we will have

$\Delta P = P_2 - P_1$

Here initial pressure is given as

$P_1 = P_o + \frac{mg}{A}$

now new pressure is given as

$P_2 = 1.59 P_1$

so we have force on the cylinder given as

$F = P_2A - mg - P_oA$

$F = 1.59(P_0 + \frac{mg}{A})A - (mg + P_0A)$

$F = 0.59(1.01 \times 10^5 \times \pi(7.24 \times 10^{-3})^2 + 0.366(9.81))$

$F = 11.93 N$

now the acceleration is given as

$F = ma$

$11.93 = 0.366 a$

$a = 32.6 m/s^2$

4 0

3 years ago

A force of 125 N is applied to a 50 kg. Mass. What is the acceleration of the mass?

grandymaker [24]

The acceleration would be 2.5 m/sec^2
A= acceleration
F= force
M= mass
A = f/m
125N/50kg=2.5 m/s^2

3 0

4 years ago

A child pushes a toy truck 2.5 m across a floor with a constant force of 22 N. How much work does the child do on the toy truck?

julsineya [31]

Answer:

55j

Explanation:

work= force × distance

3 0

3 years ago

The mass of the skateboard is 1.8kg and the mass of the skateboarder is 42kg.

Murljashka [212]

Total momentum must be conserved since there are no external forces in the horizontal direction on the skateboarder or the skateboard.

Momentum before the jump:
$P = m_1v_1 + m_2v_2 = (1.8kg)(0) + (42kg)(0) = 0$

Momentum after the jump:
$P = m_1v_1 + m_2v_2 = (1.8kg)(v_1) + (42kg)(0.3 \frac{m}{s} ) = 0$

Solving for the velocity v:
$v_1 = - \frac{m_2v_2}{m_1} = - \frac{(42kg)(0.3 \frac{m}{s} )}{1.8kg} = -7 \frac{m}{s}$

4 0

4 years ago