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3 years ago

Tides are a result of

Physics

2 answers:

Virty [35]3 years ago

6 0

The answer should be D but if its not then im sorrry, idk

Mrrafil [7]3 years ago

6 0

Tides are a result of <u>"the gravitational attraction of the Sun and Moon".</u>

An especially high tide (Spring tide) happens when the sun and moon are in line and both pull in a similar way.

Tides may appear to be straightforward at first glance, yet the intricate details of tides jumbled extraordinary logical masterminds for a considerable length of time they even driven Galileo astray into a bunk theory.

Today individuals realize that the gravitational pulls between the earth, moon and sun manage the tides. The moon, however, impacts tides the most.

The moon's gravitational pull on the earth is solid enough to pull the seas into bulge. On the off chance that no different powers were impacting everything, shores would encounter one high tide a day as the earth pivoted on its hub and coasts kept running into the seas' bulge confronting the moon.

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Using a 679 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t

sveta [45]

To solve the problem, apply the concepts related to constructive and destructive interference. For this purpose, we will start by defining the distance from the dark fringe from the central maximum in terms of the slit separation, the number of fringe the wavelength and the distance of the screen to the slit. Mathematically this is,

$y_n = \frac{(2n-1)\lambda D}{2d}$

$D = \frac{2dy_n}{(2n-1)\lambda}$

Here,

d = Slit separation

n = Number of fringe

$y_n$ = Distance of the dark fringe from the central maximum

D = Distance of the screen to the slit

$\lambda$ = Wavelength

Our values are given as,

$\lambda = 679nm = 679*10^{-9}m$

$d = 1.1mm = 1.1*10^{-3}m$

$y_{14} = 8.01cm = 8.01*10^{-2} m$

$n = 14$

Replacing,

$D = \frac{2(1.1*10^{-3})(8.01*10^{-2})}{(2(14)-1)(679*10^{-9})}$

$D = 9.61m$

Therefore the screen is located from the slit to 9.61m

7 0

4 years ago

Which part of vernier caliper is used to measure internal diameter of cylinder

BlackZzzverrR [31]

Answer:

Circled in Red...plus the scales, of course.

Explanation:

6 0

3 years ago

John is gardening and finds a tree root in the soil. He decides he will try to pull it out. He grabs onto it and uses a force of

Leya [2.2K]

Answer:

20 joules/sec

Explanation:

100/5=20

7 0

3 years ago

Which of the following positions would Earth be in if it were winter in the Northern Hemisphere?

abruzzese [7]

Answer:

Earth's tilted axis causes the seasons. Throughout the year, different parts of Earth receive the Sun's most direct rays. So, when the North Pole tilts toward the Sun, it's summer in the Northern Hemisphere. And when the South Pole tilts toward the Sun, it's winter in the Northern Hemisphere.

6 0

3 years ago

a thundercloud whose base is 500m above the ground. The potential difference between the base of the cloud and the m ground is 2

kolezko [41]

Answer:

1.6×10⁻⁶ N.

Explanation:

From the question,

F = (V/r)q......................... Equation 1

Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.

Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.

Substitute these values into equation 1

F = [(200×10⁶ )/500]×4.0×10⁻¹²

F = 1.6×10⁻⁶ N.

3 0

3 years ago