The correct answer to the question is : B) 132 Joules.
EXPLANATION :
As per the question, the mass of the gold m = 3 gram.
The initial temperature of the gold T = 21 degree celsius.
The final temperature of the gold T' = 363 degree celsius.
Hence, the change in temperature dT = T' - T
= 363 - 21 degree celsius
= 342 degree celsius.
The specific heat of the gold is given as c = 
We are asked to calculate the heat required ( dQ ) to raise the temperature of gold.
The heat required for this is calculated as -
dQ = mcDT
= 3 × 342 × 0.129 J
= 132.354 J
≈ 132 J
Hence, the correct answer is 132 J.
It’s actually C. homogeneous compound because when they combine you can’t separate them
Using the equation v(avg)=distance/time
and the equation v=v(original)+a(t)
solve for acceleration
2600=0+a(12)
a=216.66666 m/s^2
Then, you use the equation
v^2=v(original)+2a*(change in x)
2600^2=2(216.666666)*change in x
6760000/2/216.666666 = 15600 meters which is the length of the race
Then using v(avg)=x/t
15600/12= 1300 m/s
Kinetic energy , KE= [1/2]m*v^2
m = 10 kg
v=20m/s
KE = [1/][(10kg)(20m/s)^2 = [1/2](10kg)(400m^2/s^2) = 2000 joule
Answer: 2000 joule
Answer:
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Explanation:
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